Stop execution of a script called with execfile

Question

Is it possible to break the execution of a Python script called with the execfile function without using an if/else statement? I\'ve tried exit(), but it doesn\'t a

Answer 1

What's wrong with plain old exception handling?

scriptexit.py

class ScriptExit( Exception ): pass

main.py

from scriptexit import ScriptExit
print "Main Starting"
try:
    execfile( "script.py" )
except ScriptExit:
    pass
print "This should print"

script.py

from scriptexit import ScriptExit
print "Script starting"
a = False

if a == False:
    # Sanity checks. Script should break here
    raise ScriptExit( "A Good Reason" )

# I'd prefer not to put an "else" here and have to indent the rest of the code
print "this should not print"
# lots of lines below

Answer 2

main can wrap the execfile into a try/except block: sys.exit raises a SystemExit exception which main can catch in the except clause in order to continue its execution normally, if desired. I.e., in main.py:

try:
  execfile('whatever.py')
except SystemExit:
  print "sys.exit was called but I'm proceeding anyway (so there!-)."
print "so I'll print this, etc, etc"

and whatever.py can use sys.exit(0) or whatever to terminate its own execution only. Any other exception will work as well as long as it's agreed between the source to be execfiled and the source doing the execfile call -- but SystemExit is particularly suitable as its meaning is pretty clear!

Answer 3

# script.py
def main():
    print "Script starting"
    a = False

    if a == False:
        # Sanity checks. Script should break here
        # <insert magic command>    
        return;
        # I'd prefer not to put an "else" here and have to indent the rest of the code
    print "this should not print"
    # lots of lines bellow

if __name__ ==  "__main__":
    main();

I find this aspect of Python (the __name__ == "__main__", etc.) irritating.