I have my own exception based on some condition and want to raise an alert when control comes in this catch block
catch (ApplicationException ex)
{
//want t
Do you mean, a message box?
MessageBox.Show("Error Message", "Error Title", MessageBoxButtons.OK, MessageBoxIcon.Exclamation);
More information here: http://msdn.microsoft.com/en-us/library/system.windows.forms.messagebox(v=VS.100).aspx
You should try this.
ClientScript.RegisterStartupScript(this.GetType(), "myalert", "alert('Sakla Test');", true);
Simple use this to show the alert message box in code behind.
ScriptManager.RegisterStartupScript(this, this.GetType(), "script", "alert('Record Saved Sucessfully');", true);
You can try this:
Hope it works for you..
`private void validateUserEntry()
{
// Checks the value of the text.
if(serverName.Text.Length == 0)
{
// Initializes the variables to pass to the MessageBox.Show method.
string message = "You did not enter a server name. Cancel this operation?";
string caption = "Error Detected in Input";
MessageBoxButtons buttons = MessageBoxButtons.YesNo;
DialogResult result;
// Displays the MessageBox.
result = MessageBox.Show(message, caption, buttons);
if (result == System.Windows.Forms.DialogResult.Yes)
{
// Closes the parent form.
this.Close();
}
}
}`