SPARQL select optional with language

Question

I have some triples that look like this:

test:thing rdfs:label \"Non-Language Label\"
test:thing rdfs:label \"English Label\"@en
test:thing rdfs:label \"French L         


        

Answer 1

The easiest way to check the language of literals is to use the lang() function. Using this, your query can be written as:

PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#> 
PREFIX test: <http://test#> 
SELECT ?label ?preferredLabel 
WHERE { 
   test:thing rdfs:label ?label 
   OPTIONAL { 
     test:thing rdfs:label ?preferredLabel . 
     FILTER (lang(?preferredLabel) = "" || lang(?preferredLabel) = "fr") 
   } 
}

Answer 2

PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#> 
SELECT ?uri ?label ?preferredLabel
WHERE 
{
  {
   ?uri rdfs:label ?label . FILTER(LANG(?label) = "" && regex(str(?label), '(^|\\\\W)fr', 'i'))
  }
  UNION
  {
   ?uri rdfs:label ?preferredLabel . FILTER(LANG(?preferredLabel) = "fr" && regex(str(?preferredLabel), '(^|\\\\W)fr', 'i'))
  }
}

Answer 3

I don't see why you need OPTIONAL here at all. Jan's query is failing because there is no shared variable between the outer pattern and the optional so you are trying to calculate the cross product of every label for test:thing with every non/french labelled test:thing which may be huge and why the query processor is failing.

You simply want something like the following unless I've misunderstood your question

PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#> 
SELECT ?label
WHERE 
{
   test:thing rdfs:label ?label 
   FILTER(LANG(?label) = "" || LANGMATCHES(LANG(?label), "fr"))
}

If you want the two labels separately then you could do something like:

PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#> 
SELECT ?label ?preferredLabel
WHERE 
{
  {
   test:thing rdfs:label ?label . FILTER(LANG(?label) = "")
  }
  UNION
  {
   test:thing rdfs:label ?preferredLabel . FILTER(LANGMATCHES(LANG(?label), "fr"))
  }
}