Formatting the date time with Javascript

后端 未结 12 2210
暗喜
暗喜 2020-11-27 07:36

I have a date/time string like 2012-01-13 04:37:20 but I want to convert it to dd-mm-yyyy hh:mm, how can i do this?

I am using the followin

相关标签:
12条回答
  • 2020-11-27 07:43

    With Jquery, you steal datepicker's feature like that:

    $.datepicker.formatDate( "dd-M-yy", new Date())

    0 讨论(0)
  • 2020-11-27 07:47

    The best date-time handling lib in JavaSCript is moment.

    moment().format('MMMM Do YYYY, h:mm:ss a');
    
    0 讨论(0)
  • 2020-11-27 07:48

    Easily accomplished by my date-shortcode package:

    const dateShortcode = require('date-shortcode')
    dateShortcode.parse('{DD-MM-YYYY hh:mm}', '2012-01-13 04:37:20')
    //=> '13-01-2012 04:37'
    
    0 讨论(0)
  • 2020-11-27 07:58

    You can do a simple string manipulation and create js date object. See function below, which accepts date in format //yyyy-mm-dd hh:mm:ss

    DEMO here

    function toJSDate (dateTime) {
    
    var dateTime = dateTime.split(" ");//dateTime[0] = date, dateTime[1] = time
    
    var date = dateTime[0].split("-");
    var time = dateTime[1].split(":");
    
    //(year, month, day, hours, minutes, seconds, milliseconds)
    return new Date(date[0], date[1], date[2], time[0], time[1], time[2], 0);
    
    }
    
    0 讨论(0)
  • 2020-11-27 07:59

    If you don't need all the features that a library like Moment.js provides, then you can use my port of strftime. It's lightweight (1.35 KB vs. 57.9 KB minified compared to Moment.js 2.15.0) and provides most of the functionality of strftime().

    /* Port of strftime(). Compatibility notes:
     *
     * %c - formatted string is slightly different
     * %D - not implemented (use "%m/%d/%y" or "%d/%m/%y")
     * %e - space is not added
     * %E - not implemented
     * %h - not implemented (use "%b")
     * %k - space is not added
     * %n - not implemented (use "\n")
     * %O - not implemented
     * %r - not implemented (use "%I:%M:%S %p")
     * %R - not implemented (use "%H:%M")
     * %t - not implemented (use "\t")
     * %T - not implemented (use "%H:%M:%S")
     * %U - not implemented
     * %W - not implemented
     * %+ - not implemented
     * %% - not implemented (use "%")
     *
     * strftime() reference:
     * http://man7.org/linux/man-pages/man3/strftime.3.html
     *
     * Day of year (%j) code based on Joe Orost's answer:
     * http://stackoverflow.com/questions/8619879/javascript-calculate-the-day-of-the-year-1-366
     *
     * Week number (%V) code based on Taco van den Broek's prototype:
     * http://techblog.procurios.nl/k/news/view/33796/14863/calculate-iso-8601-week-and-year-in-javascript.html
     */
    function strftime(sFormat, date) {
      if (!(date instanceof Date)) date = new Date();
      var nDay = date.getDay(),
        nDate = date.getDate(),
        nMonth = date.getMonth(),
        nYear = date.getFullYear(),
        nHour = date.getHours(),
        aDays = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday'],
        aMonths = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December'],
        aDayCount = [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334],
        isLeapYear = function() {
          return (nYear%4===0 && nYear%100!==0) || nYear%400===0;
        },
        getThursday = function() {
          var target = new Date(date);
          target.setDate(nDate - ((nDay+6)%7) + 3);
          return target;
        },
        zeroPad = function(nNum, nPad) {
          return ('' + (Math.pow(10, nPad) + nNum)).slice(1);
        };
      return sFormat.replace(/%[a-z]/gi, function(sMatch) {
        return {
          '%a': aDays[nDay].slice(0,3),
          '%A': aDays[nDay],
          '%b': aMonths[nMonth].slice(0,3),
          '%B': aMonths[nMonth],
          '%c': date.toUTCString(),
          '%C': Math.floor(nYear/100),
          '%d': zeroPad(nDate, 2),
          '%e': nDate,
          '%F': date.toISOString().slice(0,10),
          '%G': getThursday().getFullYear(),
          '%g': ('' + getThursday().getFullYear()).slice(2),
          '%H': zeroPad(nHour, 2),
          '%I': zeroPad((nHour+11)%12 + 1, 2),
          '%j': zeroPad(aDayCount[nMonth] + nDate + ((nMonth>1 && isLeapYear()) ? 1 : 0), 3),
          '%k': '' + nHour,
          '%l': (nHour+11)%12 + 1,
          '%m': zeroPad(nMonth + 1, 2),
          '%M': zeroPad(date.getMinutes(), 2),
          '%p': (nHour<12) ? 'AM' : 'PM',
          '%P': (nHour<12) ? 'am' : 'pm',
          '%s': Math.round(date.getTime()/1000),
          '%S': zeroPad(date.getSeconds(), 2),
          '%u': nDay || 7,
          '%V': (function() {
                  var target = getThursday(),
                    n1stThu = target.valueOf();
                  target.setMonth(0, 1);
                  var nJan1 = target.getDay();
                  if (nJan1!==4) target.setMonth(0, 1 + ((4-nJan1)+7)%7);
                  return zeroPad(1 + Math.ceil((n1stThu-target)/604800000), 2);
                })(),
          '%w': '' + nDay,
          '%x': date.toLocaleDateString(),
          '%X': date.toLocaleTimeString(),
          '%y': ('' + nYear).slice(2),
          '%Y': nYear,
          '%z': date.toTimeString().replace(/.+GMT([+-]\d+).+/, '$1'),
          '%Z': date.toTimeString().replace(/.+\((.+?)\)$/, '$1')
        }[sMatch] || sMatch;
      });
    }
    

    Sample usage:

    // Returns "15-09-2016 16:20"
    strftime('%d-%m-%Y %H:%M');
    
    // You can optionally pass it a Date object
    // Returns "01-01-2016 21:30"
    strftime('%d-%m-%Y %H:%M', new Date('Jan 1, 2016 9:30 PM'));
    

    The latest code is available here: https://github.com/thdoan/strftime

    0 讨论(0)
  • 2020-11-27 08:00

    Your variable now is a String object and toLocaleDateString method needs a Date object. See w3schools

    0 讨论(0)
提交回复
热议问题