Do line endings differ between Windows and Linux? [closed]

Answer 1

Why not use LineNumberReader?

If you can't do that, what does the code look like?

The only difference I can think of is that you are splitting on a bad regex and that when you edit the file yourself, you get dos newlines that somehow pass your regex.

Still, for reading things one line at a time, it seems like overkill to use Scanner.

Of course, why you are parsing /etc/passwd is a hole other discussion :)

Answer 2

From Wikipedia:

• LF: Multics, Unix and Unix-like systems (GNU/Linux, AIX, Xenix, Mac OS X, FreeBSD, etc.), BeOS, Amiga, RISC OS, and others
• CR+LF: DEC RT-11 and most other early non-Unix, non-IBM OSes, CP/M, MP/M, DOS, OS/2, Microsoft Windows, Symbian OS
• CR: Commodore machines, Apple II family, Mac OS up to version 9 and OS-9

I translate this into these line endings in general:

• Windows: '\r\n'
• Mac (OS 9-): '\r'
• Mac (OS 10+): '\n'
• Unix/Linux: '\n'

You need to make your scanner/parser handle the unix version, too.

Answer 3

This works for me on Ubuntu

import java.util.Scanner;
import java.io.File;

public class test {
  public static void main(String[] args) {
    try {
      Scanner sc = new Scanner(new File("/etc/passwd"));
      String l;
      while( ( l = sc.nextLine() ) != null ) {
        String[] p = l.split(":");
        for(String pi: p) System.out.print( pi + "\t:\t" );
        System.out.println();
      }
    } catch(Exception e) { e.printStackTrace(); }
  }
}

Answer 4

You can get the standard line ending for your current OS from:

System.getProperty("line.separator")

Answer 5

The scanner is breaking at the spaces.

EDIT: The 'Scanning' Java Tutorial states:

By default, a scanner uses white space to separate tokens. (White space characters include blanks, tabs, and line terminators. For the full list, refer to the documentation for Character.isWhitespace.)

You can use the useDelimiter() method to change these defaults.