Convert []string to []byte

Question

I am looking to convert a string array to a byte array in GO so I can write it down to a disk. What is an optimal solution to encode and decode a string array ([]string

Answer 1

The gob package will do this for you http://godoc.org/encoding/gob

Example to play with http://play.golang.org/p/e0FEZm-qiS

same source code is below.

package main

import (
    "bytes"
    "encoding/gob"
    "fmt"
)

func main() {
    // store to byte array
    strs := []string{"foo", "bar"}
    buf := &bytes.Buffer{}
    gob.NewEncoder(buf).Encode(strs)
    bs := buf.Bytes()
    fmt.Printf("%q", bs)

    // Decode it back
    strs2 := []string{}
    gob.NewDecoder(buf).Decode(&strs2)
    fmt.Printf("%v", strs2)
}

Answer 2

To illustrate the problem, convert []string to []byte and then convert []byte back to []string, here's a simple solution:

package main

import (
    "encoding/binary"
    "fmt"
)

const maxInt32 = 1<<(32-1) - 1

func writeLen(b []byte, l int) []byte {
    if 0 > l || l > maxInt32 {
        panic("writeLen: invalid length")
    }
    var lb [4]byte
    binary.BigEndian.PutUint32(lb[:], uint32(l))
    return append(b, lb[:]...)
}

func readLen(b []byte) ([]byte, int) {
    if len(b) < 4 {
        panic("readLen: invalid length")
    }
    l := binary.BigEndian.Uint32(b)
    if l > maxInt32 {
        panic("readLen: invalid length")
    }
    return b[4:], int(l)
}

func Decode(b []byte) []string {
    b, ls := readLen(b)
    s := make([]string, ls)
    for i := range s {
        b, ls = readLen(b)
        s[i] = string(b[:ls])
        b = b[ls:]
    }
    return s
}

func Encode(s []string) []byte {
    var b []byte
    b = writeLen(b, len(s))
    for _, ss := range s {
        b = writeLen(b, len(ss))
        b = append(b, ss...)
    }
    return b
}

func codecEqual(s []string) bool {
    return fmt.Sprint(s) == fmt.Sprint(Decode(Encode(s)))
}

func main() {
    var s []string
    fmt.Println("equal", codecEqual(s))
    s = []string{"", "a", "bc"}
    e := Encode(s)
    d := Decode(e)
    fmt.Println("s", len(s), s)
    fmt.Println("e", len(e), e)
    fmt.Println("d", len(d), d)
    fmt.Println("equal", codecEqual(s))
}

Output:

equal true
s 3 [ a bc]
e 19 [0 0 0 3 0 0 0 0 0 0 0 1 97 0 0 0 2 98 99]
d 3 [ a bc]
equal true

Answer 3

Lets ignore the fact that this is Go for a second. The first thing you need is a serialization format to marshal the []string into.

There are many option here. You could build your own or use a library. I am going to assume you don't want to build your own and jump to serialization formats go supports.

In all examples, data is the []string and fp is the file you are reading/writing to. Errors are being ignored, check the returns of functions to handle errors.

Gob

Gob is a go only binary format. It should be relatively space efficient as the number of strings increases.

enc := gob.NewEncoder(fp)
enc.Encode(data)

Reading is also simple

var data []string
dec := gob.NewDecoder(fp)
dec.Decode(&data)

Gob is simple and to the point. However, the format is only readable with other Go code.

Json

Next is json. Json is a format used just about everywhere. This format is just as easy to use.

enc := json.NewEncoder(fp)
enc.Encode(data)

And for reading:

var data []string
dec := json.NewDecoder(fp)
dec.Decode(&data)

XML

XML is another common format. However, it has pretty high overhead and not as easy to use. While you could just do the same you did for gob and json, proper xml requires a root tag. In this case, we are using the root tag "Strings" and each string is wrapped in an "S" tag.

type Strings struct {
    S []string
}

enc := xml.NewEncoder(fp)
enc.Encode(Strings{data})

var x Strings
dec := xml.NewDecoder(fp)
dec.Decode(&x)
data := x.S

CSV

CSV is different from the others. You have two options, use one record with n rows or n records with 1 row. The following example uses n records. It would be boring if I used one record. It would look too much like the others. CSV can ONLY hold strings.

enc := csv.NewWriter(fp)
for _, v := range data {
    enc.Write([]string{v})
}
enc.Flush()

To read:

var err error
var data string
dec := csv.NewReader(fp)
for err == nil {        // reading ends when an error is reached (perhaps io.EOF)
    var s []string

    s, err = dec.Read()
    if len(s) > 0 {
        data = append(data, s[0])
    }
}

---

Which format you use is a matter of preference. There are many other possible encodings that I have not mentioned. For example, there is an external library called bencode. I don't personally like bencode, but it works. It is the same encoding used by bittorrent metadata files.

If you want to make your own encoding, encoding/binary is a good place to start. That would allow you to make the most compact file possible, but I hardly thing it is worth the effort.

Answer 4

You can do something like this:

var lines = []string
var ctx = []byte{}
for _, s := range lines {
    ctx = append(ctx, []byte(s)...)
}

Answer 5

I would suggest to use PutUvarint and Uvarint for storing/retrieving len(s) and using []byte(str) to pass str to some io.Writer. With a string length known from Uvarint, one can buf := make([]byte, n) and pass the buf to some io.Reader.

Prepend the whole thing with length of the string array and repeat the above for all of its items. Reading the whole thing back is again reading first the outer length and repeating n-times the item read.

Answer 6

to convert []string to []byte

var str = []string{"str1","str2"}
var x = []byte{}

for i:=0; i<len(str); i++{
    b := []byte(str[i])
    for j:=0; j<len(b); j++{
        x = append(x,b[j])
    }
}

to convert []byte to string

str := ""
var x = []byte{'c','a','t'}
for i := 0; i < len(x); i++ {
    str += string(x[i])
}