I\'m trying to get the datestamp on the file in mm/dd/yyyy format
time.ctime(os.path.getmtime(file))
gives me detailed time stamp Fri Jun
You want to use time.strftime() to format the timestamp; convert it to a time tuple first using either time.gmtime() or time.localtime():
time.strftime('%m/%d/%Y', time.gmtime(os.path.getmtime(file)))
from datetime import datetime
from os.path import getmtime
datetime.fromtimestamp(getmtime(file)).strftime('%m/%d/%Y')
You can create the datetime object using the ctime str like you mention and then format it back to a string of any format.
str1 = time.ctime(os.path.getmtime(file)) # Fri Jun 07 16:54:31 2013
datetime_object = datetime.strptime(str1, '%a %b %d %H:%M:%S %Y')
datetime_object.strftime("%m/%d/%Y") # 06/07/2013
This way you don't have to deal with timezones + absolute timestamp from the Epoch
Credit: Converting string into datetime
Linking: How to get file creation & modification date/times in Python?
http://strftime.org/