Webpack: How can we *conditionally* use a plugin?

Question

In Webpack, I have the following plugins:

plugins: [
        new ExtractTextPlugin(\'styles.css\'),
        new webpack.optimize.UglifyJsPlugin({
            com         


        

Answer 1

You can use noop-webpack-plugin (noop means no operation):

const isProd = process.env.NODE_ENV === 'production';
const noop = require('noop-webpack-plugin');
// ...
plugins: [
    isProd ? new Plugin() : noop(),
]

Or better/recommended solution with no additional module:

const isProd = process.env.NODE_ENV === 'production';
// ...
plugins: [
    isProd ? new Plugin() : false,
].filter(Boolean)
// filter(Boolean) removes items from plugins array which evaluate to
// false (so you can use e.g. 0 instead of false: `new Plugin() : 0`)