Creating a LINQ Expression where parameter equals object

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野性不改 2021-02-07 00:18

Given a primitive value age I know how to create an expression like this:

//assuming: age is an int or some other primitive type
employee => empl         


        
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  • 2021-02-07 00:58

    In addition to what has been mentioned in previous answers. A more specific solution would go as such:

    public static Expression CreateExpression<T>(string propertyName, object valueToCompare)
    {
        // get the type of entity
        var entityType = typeof(T);
        // get the type of the value object
        var valueType = valueToCompare.GetType();
        var entityProperty = entityType.GetProperty(propertyName);
        var propertyType = entityProperty.PropertyType;
    
    
        // Expression: "entity"
        var parameter = Expression.Parameter(entityType, "entity");
    
        // check if the property type is a value type
        // only value types work 
        if (propertyType.IsValueType || propertyType.Equals(typeof(string)))
        {
            // Expression: entity.Property == value
            return Expression.Equal(
                Expression.Property(parameter, entityProperty),
                Expression.Constant(valueToCompare)
            );
        }
        // if not, then use the key
        else
        {
            // get the key property
            var keyProperty = propertyType.GetProperties().FirstOrDefault(p => p.GetCustomAttributes(typeof(KeyAttribute), false).Length > 0);
    
            // Expression: entity.Property.Key == value.Key
            return Expression.Equal(
                Expression.Property(
                    Expression.Property(parameter, entityProperty),
                    keyProperty
                ),
                Expression.Constant(
                    keyProperty.GetValue(valueToCompare),
                    keyProperty.PropertyType
                )
            );
        }
    }
    

    IMPORTANT POINTS :

    1. Make sure to check for nulls
    2. Make sure propertyType and valueType are compatible (either they are the same type or are convertible)
    3. Several assumptions are made here (e.g. that you do assign a KeyAttribute)
    4. This code is not tested, so it is not exactly copy/paste ready.

    Hope that helps.

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  • 2021-02-07 00:58

    Give the code below a run. I wanted to test your assumption that e => e.Location == location is compiling into something that can be constructed with Expression.Equal, Expression.Property, and Expression.Constant.

        class Program {
           static void Main(string[] args) {
              var location = new Location();
              Expression<Func<Employee, bool>> expression = e => e.Location == location;
    
              var untypedBody = expression.Body;
    
              //The untyped body is a BinaryExpression
               Debug.Assert(
                  typeof(BinaryExpression).IsAssignableFrom(untypedBody.GetType()), 
                  "Not Expression.Equal");
    
               var body = (BinaryExpression)untypedBody;
               var untypedLeft = body.Left;
               var untypedRight = body.Right;
    
               //The untyped left expression is a MemberExpression
               Debug.Assert(
                  typeof(MemberExpression).IsAssignableFrom(untypedLeft.GetType()), 
                  "Not Expression.Property");
    
               ////The untyped right expression is a ConstantExpression
              //Debug.Assert(
              //   typeof(ConstantExpression).IsAssignableFrom(untypedRight.GetType()),                 
              //   "Not Expression.Constant");
    
              //The untyped right expression is a MemberExpression?
              Debug.Assert(
                   typeof(MemberExpression).IsAssignableFrom(untypedRight.GetType())));
        }
    }
    
    public class Employee
    {
        public Location Location { get; set; }
    }
    
    public class Location { }
    

    It seems like it isn't, and its because the right expression isn't a Constant. To see this, uncomment the commented out code.

    What I don't understand is why the right expression is a MemberExpression. Perhaps someone who knows the linq expression compiler can shed more light onto this then I can.

    Edit: This may have to do with closure in lambdas - a class is created behind the scenes which contains the closed over variables. The location might then be a member of that class. I'm not sure about this, but it's what I suspect.

    This post may shed additional light on the situation.

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  • 2021-02-07 01:09

    You can't do that because EF doesn't know how to translate equality comparisons on Location into a SQL expression.

    However, if you know what properties of Location you want to compare, you can do this with anonymous types:

    var location = GetCurrentLocation();
    var locationObj = new { location.LocationName, location.LocationDescription };
    employees = DataContext.Employees.Where(e => new { e.Location.LocationName, e.Location.Description } == locationObj);
    

    Of course that's equivalent to:

    var location = GetCurrentLocation();
    employees = DataContext.Employees.Where(e => e.Location.LocationName == location.Name && 
                                                 e.Location.Description == location.Description);
    
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