RegEx for no whitespace at the beginning and end

Question

I want to design an expression for not allowing whitespace at the beginning and at the end of a string, but allowing in the middle of the string.

The regex I\'ve tri

Answer 1

How about:

^\S.+\S$

This will match any string that doesn't begin or end with any kind of space.

Answer 2

pattern="^[^\s]+[-a-zA-Z\s]+([-a-zA-Z]+)*$" This will help you accept only characters and wont allow spaces at the start nor whitespaces.

Answer 3

^[^\s].+[^\s]$

That's it!!!! it allows any string that contains any caracter (a part from \n) without whitespace at the beginning or end; in case you want \n in the middle there is an option s that you have to replace .+ by [.\n]+

Answer 4

As a modification of @Aprillion's answer, I prefer:

^\S$|^\S[ \S]*\S$

• It will not match a space at the beginning, end, or both.
• It matches any number of spaces between a non-whitespace character at the beginning and end of a string.
• It also matches only a single non-whitespace character (unlike many of the answers here).
• It will not match any newline (\n), \r, \t, \f, nor \v in the string (unlike Aprillion's answer). I realize this isn't explicit to the question, but it's a useful distinction.

Answer 5

This is the regex for no white space at the begining nor at the end but only one between. Also works without a 3 character limit :

\^([^\s]*[A-Za-z0-9]\s{0,1})[^\s]*$\ - just remove {0,1} and add * in order to have limitless space between.

Answer 6

^[^0-9 ]{1}([a-zA-Z]+\s{1})+[a-zA-Z]+$

-for No more than one whitespaces in between , No spaces in first and last.

^[^0-9 ]{1}([a-zA-Z ])+[a-zA-Z]+$

-for more than one whitespaces in between , No spaces in first and last.