I want to give the possibility to match string with wildcard *
.
Example
$mystring = \'dir/folder1/file\';
$pattern = \'dir/*/file\';
string
$pattern = str_replace( '\*' , '.+?', $pattern); // at least one character
There is no need for preg_match
here. PHP has a wildcard comparison function, specifically made for such cases:
fnmatch()
And fnmatch('dir/*/file', 'dir/folder1/file')
would likely already work for you. But beware that the *
wildcard would likewise add further slashes, like preg_match would.
.+?
Causes non-greedy matching for all characters. This is NOT equal to "*" becuase it will not match the empty string.
The following pattern will match the empty string too:
.*?
so...
stringMatchWithWildcard ("hello", "hel*lo"); // will give true
The one problem you'll have is that the call to preg_quote()
will escape the asterisk character. Given that, your str_replace()
will replace the *
, but not the escape character in front of it.
Therefore you should change the str_replace('*' ..)
with str_replace('\*'..)
You should just use .*
instead.
$pattern = str_replace( '*' , '.*', $pattern); //> This is the important replace
Edit: Also your ^
and $
were in the wrong order.
<?php
function stringMatchWithWildcard($source,$pattern) {
$pattern = preg_quote($pattern,'/');
$pattern = str_replace( '\*' , '.*', $pattern);
return preg_match( '/^' . $pattern . '$/i' , $source );
}
$mystring = 'dir/folder1/file';
$pattern = 'dir/*/file';
echo stringMatchWithWildcard($mystring,$pattern);
$mystring = 'string bl#abla;y';
$pattern = 'string*y';
echo stringMatchWithWildcard($mystring,$pattern);
Working demo: http://www.ideone.com/mGqp2
You're mixing up ending ($
) and beginning (^
). This:
preg_match( '/$' . $pattern . '^/i' , $source );
Should be:
preg_match( '/^' . $pattern . '$/i' , $source );