How can I iterate in reverse over a map in C++?

Question

I\'m having trouble iterating in reverse over a map in GCC C++. When I use a reverse iterator, it seems I can\'t assign anything to it - the compiler complains. I\'m working aro

Answer 1

Here's an example of iterating backward through a std::map:

#include <iostream>
#include <map>
#include <string>

int main() {
    std::map<std::string, std::string> m;
    m["a"] = "1";
    m["b"] = "2";
    m["c"] = "3";

    for (auto iter = m.rbegin(); iter != m.rend(); ++iter) {
        std::cout << iter->first << ": " << iter->second << std::endl;
    }
}

If you are pre-C++11, you'll just need to spell out auto, which is:

std::map<std::string, std::string>::reverse_iterator

Note that if you're using boost, you can use a range-based for loop with a reverse adapter:

#include <boost/range/adaptor/reversed.hpp>

for (auto& iter : boost::adaptors::reverse(m)) {
    std::cout << iter.first << ": " << iter.second << std::endl;
}

Answer 2

Since C++20 you can make use of the range adaptor std::views::reverse from the Ranges library. If you add this to a range-based for loop with structured binding, iterating backwards over an std::map could be done as follows:

#include <map>
#include <ranges>
#include <iostream>

int main() {
    std::map<std::string, int> m = { {"a", 1}, {"b", 2}, {"c", 3} };

    for (auto const& [k, v] : m | std::views::reverse)
        std::cout << k << " => " << v << std::endl;

    return 0;
}

Output:

c => 3
b => 2
a => 1

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