How to chain a Promise.all with other Promises?

Question

I want to execute my code in the following order:

1. Promise 1
2. Wait for 1 to be done, then do Promise 2+3 at the same time
3. Final function waits for

Answer 1

I know it's an old thread, but isn't

() => {return Promise.all([getPromise2(), getPromise3()]);}

a little superfluous? The idea of fat arrow is that you can write it as:

() => Promise.all([getPromise2(), getPromise3()])

which makes the resulting code somewhat clearer:

getPromise1().then(() => Promise.all([getPromise2(), getPromise3()]))
.then((args) => console.log(args)); // result from 2 and 3

Anyway, thanks for the answer, I was stuck with this :)

Answer 2

Just return Promise.all(...

getPromise1().then(() => {
  return Promise.all([getPromise2(), getPromise3()]);
}).then((args) => console.log(args)); // result from 2 and 3