I\'m very confused. Why can\'t I use scale and rotate at the same time? I\'ve tried this, but it does not work:
.rotate-img{
-webkit-transform:scale(2,2);
You can rotate an image with CSS using the transform
property with a rotate(**deg)
value
.rotate-img {
-webkit-transform : rotate(90deg) scale(0.2); /* Chrome, Opera 15+, Safari 3.1+ */
-ms-transform : rotate(90deg) scale(0.2); /* IE 9 */
transform : rotate(90deg) scale(0.2); /* Firefox 16+, IE 10+, Opera */
left : -200px;
position: relative;
}
<img class="rotate-img" src="https://appharbor.com/assets/images/stackoverflow-logo.png" />
When applying transform
on multiple lines, it's like any other CSS property, and it gets overwritten so only the last line is used, just like with something like :
.myclass {
top: 100px;
top: 400px;
}
only the last one would apply, so you'll need to put all the transformations in one transform
.
Well, building on top of adeneo's answer, one that includes all browers capable of CSS transform.
.rotate-img {
-webkit-transform: rotate(90deg) scale(2.2); /* Chrome 4+, Op 15+, Saf 3.1, iOS Saf 3.2+ */
-moz-transform: rotate(90deg) scale(2.2); /* Fx 3.5-15 */
-ms-transform: rotate(90deg) scale(2.2); /* IE 9 */
-o-transform: rotate(90deg) scale(2.2); /* Op 10.5-12 */
transform: rotate(90deg) scale(2.2); /* Fx 16+, IE 10+ */
margin: 10% 0 0 20%;
}
See extended JS Fiddle.
You do not need to write code separately to use both rotate and scale u can use it look like this :
transform: scale(1.3) rotate(7deg);
You can scale & rotate at the same time, but you HAVE to do it on the same line, otherwise you overwrite the prievius value with the new value.
let htmlElement = document.getElementById("rotate-img");
let scaleX = -0.3;
let scaleY = 0.2;
let angle = 45 ;
// NOTICE!! THE BACK-TICKS, not regular quotes. Will decode variables inside before printing.
// Code for Safari
htmlElement.style.WebkitTransform = `scale( ${scaleX}, ${scaleY} ) rotate( ${angle}deg )`;
// Code for IE9
htmlElement.style.msTransform = `scale( ${scaleX}, ${scaleY} ) rotate( ${angle}deg )`;
// Standard syntax
htmlElement.style.transform = `scale( ${scaleX}, ${scaleY} ) rotate( ${angle}deg )`;
<img id="rotate-img" src="https://appharbor.com/assets/images/stackoverflow-logo.png" />
Also notice that any already existing style on that element will be overwritten, unless you save that style into a (string-)variable first & add (append or concatenate) the new styles to that saved variable & then add the whole variable back onto the html-element.