regex over multiple lines in Groovy

Question

I have a multiple line string like following:

END IF;

EXECUTE IMMEDIATE \' CREATE INDEX #idx1
      ON somename ( row         


        

Answer 1

The following should work in Groovy.

def s = """
END IF;

EXECUTE IMMEDIATE ' CREATE INDEX #idx1
      ON somename ( row_id,
                           something)';

   IF v_sys_error <> 0 THEN
      GOTO SQL_ERROR;

   END IF;
"""

def expect = """
EXECUTE IMMEDIATE ' CREATE INDEX #idx1
      ON somename ( row_id,
                           something)';
""".trim()

def exe = s =~ /(?ms)(EXECUTE.*?;)/

assert expect == exe[0][1]

Answer 2

(?m) makes the regex multiline - allows you to match beginning (^) and end ($) of string operators (in this case, to match the beginnings and ends of individual lines, rather than the whole string):

/(?m)(EXECUTE).*?;/

(?s) - dotall flag - makes the regex match newlines with . (dot) operators:

/(?s)(EXECUTE).*?;/

Answer 3

I had the same question and the other two answeres pointed me in the right direction. In this particular case, you want to be able to use patterns (and select groups) that span multiple lines, i.e. you want the dot to also match newline characters. Default behaviour does not match newlines. That is why you need to use the dotall (s) flag:

/(?s)(EXECUTE).*?;/

This is how you specify flags in groovy patterns.

For testing different patterns and flags I found RegExr quite useful.