how to pass a variable through the require() or include() function of php?

Question

when I use this:

require(\"diggstyle_code.php?page=$page_no\");

the warning is :failed to open stream: No error in C:\\xampp\\htdocs\\4ajax\\ga

Answer 1

I had this problem and I noticed if you use http:// in your url then it doesn't work

Answer 2

this should work, but it's quite a dirty hack:

$_GET['page'] = $page_no;
require('diggstyle_code.php');

you probably want to refactor your code to use functions and/or objects and call them from your files instead of including them (spaghetti code alert)

Answer 3

If your variable is global, there's no need to "pass"it, it is there already: PHP variable scope.

The answer then is, don't do anything, if $page_no exists in the file in which you call require(), it will be available in the included file.

Answer 4

if I've correctly understood, what you need is to call the file diggstyle_code.php passing an argument, so that no one can call that file and make it work, rather than your main file. Am I right?

Thus supposing that your "main.php" has the lines

require("diggstyle_code.php?page=$page_no");

it means that: if anyone calls "main.php" gets diggstyle_code.php running. But if anybody in any manner calls directly diggstyle_code.php he/she shoudl get nothing.

If I am right on my understanding, a way to achieve this, is to include into the main file a variable or a constant, that will be scoped by diggstyle_code.php

Thus for instance: 'main.php'

<?php
define("_VERIFICATION_", "y");
require("diggstyle_code.php");
?>

and now diggstyle_code.php

<?php
if ( _VERIFICATION_ == "y" ) {
//Here the code should be executed
} else {
// Something else
}
?>

Answer 5

require, require_once, include and include_once try to include files from the filesystem in the current file.

Since there's no files named diggstyle_code.php?page=1, it's totally logical that PHP can't find it.

You can't pass values that way, however, any variable declared in the current file will be accessible in the included files.

Answer 6

require doesn't pull the file from the web server - it should refer to a file on the filesystem instead.

Calling include or require just tells PHP to paste the contents of the given file in your code at this place, nothing more than that.