PHP: Using a variable inside a double quotes

Question

please check the following code.

$imagebaseurl = \'support/content_editor/uploads/$name\';

The $imagebaseurl is a variable th

Answer 1

$imagebaseurl = 'support/content_editor/uploads/' . $name;

or

$imagebaseurl = "support/content_editor/uploads/{$name}";

Note that if you use double quotes, you can also write the above as:

$imagebaseurl = "support/content_editor/uploads/$name";

It's good though to get in the habit of using {$...} in double quotes instead of only $..., for times where you need to insert the variable in a string where it's not obvious to PHP which part is the variable and which part is the string.

If you want the best performance, use string concatenation with single quotes.

Answer 2

I couldn't disagree more with the previous post.

I'd almost go as far to call it bad practice to use

$varname = 'EXAMPLE';

$fulltext = "This is an $varname";

Its more maintainable, from my experience, to utilize a good friend of mine known as sprintf();

define('CONST_NAME', 'This is an example of a better %s');
define('EXAMPLE', sprintf(CONST_NAME, 'practice'));

echo EXAMPLE;

Why? The first one may seem more clear, but the second one is much more re-usable. I recommend utilizing sprintf over the php magic double quote nonesense which exists, literally, in NO other language.

http://php.net/manual/en/function.sprintf.php

This is also the practice used very similar to C#, and many other languages.

See also: https://msdn.microsoft.com/en-us/library/system.string.format(v=vs.110).aspx