Python glob but against a list of strings rather than the filesystem

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被撕碎了的回忆 2021-02-06 21:24

I want to be able to match a pattern in glob format to a list of strings, rather than to actual files in the filesystem. Is there any way to do this, or convert a glob

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  • 2021-02-06 21:30

    Here is a glob that can deal with escaped punctuation. It does not stop on path separators. I'm posting it here because it matches the title of the question.

    To use on a list:

    rex = glob_to_re(glob_pattern)
    rex = r'(?s:%s)\Z' % rex # Can match newline; match whole string.
    rex = re.compile(rex)
    matches = [name for name in names if rex.match(name)]
    

    Here's the code:

    import re as _re
    
    class GlobSyntaxError(SyntaxError):
        pass
    
    def glob_to_re(pattern):
        r"""
        Given pattern, a unicode string, return the equivalent regular expression.
        Any special character * ? [ ! - ] \ can be escaped by preceding it with 
        backslash ('\') in the pattern.  Forward-slashes ('/') and escaped 
        backslashes ('\\') are treated as ordinary characters, not boundaries.
    
        Here is the language glob_to_re understands.
        Earlier alternatives within rules have precedence.  
            pattern = item*
            item    = '*'  |  '?'  |  '[!' set ']'  |  '[' set ']'  |  literal
            set     = element element*
            element = literal '-' literal  |  literal
            literal = '\' char  |  char other than \  [  ] and sometimes -
        glob_to_re does not understand "{a,b...}".
        """
        # (Note: the docstring above is r""" ... """ to preserve backslashes.)
        def expect_char(i, context):
            if i >= len(pattern):
                s = "Unfinished %s: %r, position %d." % (context, pattern, i)
                raise GlobSyntaxError(s)
        
        def literal_to_re(i, context="pattern", bad="[]"):
            if pattern[i] == '\\':
                i += 1
                expect_char(i, "backslashed literal")
            else:
                if pattern[i] in bad:
                    s = "Unexpected %r in %s: %r, position %d." \
                        % (pattern[i], context, pattern, i)
                    raise GlobSyntaxError(s)
            return _re.escape(pattern[i]), i + 1
    
        def set_to_re(i):
            assert pattern[i] == '['
            set_re = "["
            i += 1
            try:
                if pattern[i] == '!':
                    set_re += '^'
                    i += 1
                while True:
                    lit_re, i = literal_to_re(i, "character set", bad="[-]")
                    set_re += lit_re
                    if pattern[i] == '-':
                        set_re += '-'
                        i += 1
                        expect_char(i, "character set range")
                        lit_re, i = literal_to_re(i, "character set range", bad="[-]")
                        set_re += lit_re
                    if pattern[i] == ']':
                        return set_re + ']', i + 1
                    
            except IndexError:
                expect_char(i, "character set")  # Trigger "unfinished" error.
    
        i = 0
        re_pat = ""
        while i < len(pattern):
            if pattern[i] == '*':
                re_pat += ".*"
                i += 1
            elif pattern[i] == '?':
                re_pat += "."
                i += 1
            elif pattern[i] == '[':
                set_re, i = set_to_re(i)
                re_pat += set_re
            else:
                lit_re, i = literal_to_re(i)
                re_pat += lit_re
        return re_pat
    
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  • 2021-02-06 21:31

    The glob module uses the fnmatch module for individual path elements.

    That means the path is split into the directory name and the filename, and if the directory name contains meta characters (contains any of the characters [, * or ?) then these are expanded recursively.

    If you have a list of strings that are simple filenames, then just using the fnmatch.filter() function is enough:

    import fnmatch
    
    matching = fnmatch.filter(filenames, pattern)
    

    but if they contain full paths, you need to do more work as the regular expression generated doesn't take path segments into account (wildcards don't exclude the separators nor are they adjusted for cross-platform path matching).

    You can construct a simple trie from the paths, then match your pattern against that:

    import fnmatch
    import glob
    import os.path
    from itertools import product
    
    
    # Cross-Python dictionary views on the keys 
    if hasattr(dict, 'viewkeys'):
        # Python 2
        def _viewkeys(d):
            return d.viewkeys()
    else:
        # Python 3
        def _viewkeys(d):
            return d.keys()
    
    
    def _in_trie(trie, path):
        """Determine if path is completely in trie"""
        current = trie
        for elem in path:
            try:
                current = current[elem]
            except KeyError:
                return False
        return None in current
    
    
    def find_matching_paths(paths, pattern):
        """Produce a list of paths that match the pattern.
    
        * paths is a list of strings representing filesystem paths
        * pattern is a glob pattern as supported by the fnmatch module
    
        """
        if os.altsep:  # normalise
            pattern = pattern.replace(os.altsep, os.sep)
        pattern = pattern.split(os.sep)
    
        # build a trie out of path elements; efficiently search on prefixes
        path_trie = {}
        for path in paths:
            if os.altsep:  # normalise
                path = path.replace(os.altsep, os.sep)
            _, path = os.path.splitdrive(path)
            elems = path.split(os.sep)
            current = path_trie
            for elem in elems:
                current = current.setdefault(elem, {})
            current.setdefault(None, None)  # sentinel
    
        matching = []
    
        current_level = [path_trie]
        for subpattern in pattern:
            if not glob.has_magic(subpattern):
                # plain element, element must be in the trie or there are
                # 0 matches
                if not any(subpattern in d for d in current_level):
                    return []
                matching.append([subpattern])
                current_level = [d[subpattern] for d in current_level if subpattern in d]
            else:
                # match all next levels in the trie that match the pattern
                matched_names = fnmatch.filter({k for d in current_level for k in d}, subpattern)
                if not matched_names:
                    # nothing found
                    return []
                matching.append(matched_names)
                current_level = [d[n] for d in current_level for n in _viewkeys(d) & set(matched_names)]
    
        return [os.sep.join(p) for p in product(*matching)
                if _in_trie(path_trie, p)]
    

    This mouthful can quickly find matches using globs anywhere along the path:

    >>> paths = ['/foo/bar/baz', '/spam/eggs/baz', '/foo/bar/bar']
    >>> find_matching_paths(paths, '/foo/bar/*')
    ['/foo/bar/baz', '/foo/bar/bar']
    >>> find_matching_paths(paths, '/*/bar/b*')
    ['/foo/bar/baz', '/foo/bar/bar']
    >>> find_matching_paths(paths, '/*/[be]*/b*')
    ['/foo/bar/baz', '/foo/bar/bar', '/spam/eggs/baz']
    
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  • 2021-02-06 21:36

    never mind, I found it. I want the fnmatch module.

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  • 2021-02-06 21:38

    While fnmatch.fnmatch can be used directly to check whether a pattern matches a filename or not, you can also use the fnmatch.translate method to generate the regex out of the given fnmatch pattern:

    >>> import fnmatch
    >>> fnmatch.translate('*.txt')
    '.*\\.txt\\Z(?ms)'
    

    From the documenation:

    fnmatch.translate(pattern)

    Return the shell-style pattern converted to a regular expression.

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  • 2021-02-06 21:40

    Good artists copy; great artists steal.

    I stole ;)

    fnmatch.translate translates globs ? and * to regex . and .* respectively. I tweaked it not to.

    import re
    
    def glob2re(pat):
        """Translate a shell PATTERN to a regular expression.
    
        There is no way to quote meta-characters.
        """
    
        i, n = 0, len(pat)
        res = ''
        while i < n:
            c = pat[i]
            i = i+1
            if c == '*':
                #res = res + '.*'
                res = res + '[^/]*'
            elif c == '?':
                #res = res + '.'
                res = res + '[^/]'
            elif c == '[':
                j = i
                if j < n and pat[j] == '!':
                    j = j+1
                if j < n and pat[j] == ']':
                    j = j+1
                while j < n and pat[j] != ']':
                    j = j+1
                if j >= n:
                    res = res + '\\['
                else:
                    stuff = pat[i:j].replace('\\','\\\\')
                    i = j+1
                    if stuff[0] == '!':
                        stuff = '^' + stuff[1:]
                    elif stuff[0] == '^':
                        stuff = '\\' + stuff
                    res = '%s[%s]' % (res, stuff)
            else:
                res = res + re.escape(c)
        return res + '\Z(?ms)'
    

    This one à la fnmatch.filter, both re.match and re.search work.

    def glob_filter(names,pat):
        return (name for name in names if re.match(glob2re(pat),name))
    

    Glob patterns and strings found on this page pass test.

    pat_dict = {
                'a/b/*/f.txt': ['a/b/c/f.txt', 'a/b/q/f.txt', 'a/b/c/d/f.txt','a/b/c/d/e/f.txt'],
                '/foo/bar/*': ['/foo/bar/baz', '/spam/eggs/baz', '/foo/bar/bar'],
                '/*/bar/b*': ['/foo/bar/baz', '/foo/bar/bar'],
                '/*/[be]*/b*': ['/foo/bar/baz', '/foo/bar/bar'],
                '/foo*/bar': ['/foolicious/spamfantastic/bar', '/foolicious/bar']
    
            }
    for pat in pat_dict:
        print('pattern :\t{}\nstrings :\t{}'.format(pat,pat_dict[pat]))
        print('matched :\t{}\n'.format(list(glob_filter(pat_dict[pat],pat))))
    
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  • 2021-02-06 21:42

    Can't say how efficient it is, but it is much less verbose, much less complicated, more complete, and possibly more secure/reliable than other solutions.

    Supported syntax:

    • * -- matches zero or more characters.
    • ** (actually, it's either **/ or /**) -- matches zero or more subdirectories.
    • ? -- matches one character.
    • [] -- matches one character within brackets.
    • [!] -- matches one character not within brackets.
    • Due to escaping with \, only / can be used as a path separator.

    Order of operation:

    1. Escape special RE chars in glob.
    2. Generate RE for tokenization of escaped glob.
    3. Replace escaped glob tokens by equivalent RE.
    import re
    from sys import hexversion, implementation
    # Support for insertion-preserving/ordered dicts became language feature in Python 3.7, but works in CPython since 3.6.
    if hexversion >= 0x03070000 or (implementation.name == 'cpython' and hexversion >= 0x03060000):
        ordered_dict = dict
    else:
        from collections import OrderedDict as ordered_dict
    
    escaped_glob_tokens_to_re = ordered_dict((
        # Order of ``**/`` and ``/**`` in RE tokenization pattern doesn't matter because ``**/`` will be caught first no matter what, making ``/**`` the only option later on.
        # W/o leading or trailing ``/`` two consecutive asterisks will be treated as literals.
        ('/\*\*', '(?:/.+?)*'), # Edge-case #1. Catches recursive globs in the middle of path. Requires edge case #2 handled after this case.
        ('\*\*/', '(?:^.+?/)*'), # Edge-case #2. Catches recursive globs at the start of path. Requires edge case #1 handled before this case. ``^`` is used to ensure proper location for ``**/``.
        ('\*', '[^/]*?'), # ``[^/]*?`` is used to ensure that ``*`` won't match subdirs, as with naive ``.*?`` solution.
        ('\?', '.'),
        ('\[\*\]', '\*'), # Escaped special glob character.
        ('\[\?\]', '\?'), # Escaped special glob character.
        ('\[!', '[^'), # Requires ordered dict, so that ``\[!`` preceded ``\[`` in RE pattern. Needed mostly to differentiate between ``!`` used within character class ``[]`` and outside of it, to avoid faulty conversion.
        ('\[', '['),
        ('\]', ']'),
    ))
    
    escaped_glob_replacement = re.compile('(%s)' % '|'.join(escaped_glob_tokens_to_re).replace('\\', '\\\\\\'))
    
    def glob_to_re(pattern):
        return escaped_glob_replacement.sub(lambda match: escaped_glob_tokens_to_re[match.group(0)], re.escape(pattern))
    
    if __name__ == '__main__':
        validity_paths_globs = (
            (True, 'foo.py', 'foo.py'),
            (True, 'foo.py', 'fo[o].py'),
            (True, 'fob.py', 'fo[!o].py'),
            (True, '*foo.py', '[*]foo.py'),
            (True, 'foo.py', '**/foo.py'),
            (True, 'baz/duck/bar/bam/quack/foo.py', '**/bar/**/foo.py'),
            (True, 'bar/foo.py', '**/foo.py'),
            (True, 'bar/baz/foo.py', 'bar/**'),
            (False, 'bar/baz/foo.py', 'bar/*'),
            (False, 'bar/baz/foo.py', 'bar**/foo.py'),
            (True, 'bar/baz/foo.py', 'bar/**/foo.py'),
            (True, 'bar/baz/wut/foo.py', 'bar/**/foo.py'),
        )
        results = []
        for seg in validity_paths_globs:
            valid, path, glob_pat = seg
            print('valid:', valid)
            print('path:', path)
            print('glob pattern:', glob_pat)
            re_pat = glob_to_re(glob_pat)
            print('RE pattern:', re_pat)
            match = re.fullmatch(re_pat, path)
            print('match:', match)
            result = bool(match) == valid
            results.append(result)
            print('result was expected:', result)
            print('-'*79)
        print('all results were expected:', all(results))
        print('='*79)
    
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