with $location.search(): how to remove a parameter from the url when it's null

Question

$location.search() to set an url

the search parameter which is passed to the search() is set by a form. selecting and deselecting an element ca

Answer 1

You can use $location.search({}) to clear all at once.

Answer 2

You can also do:

var search = $location.search();
if (search.parameter == 'null') {
  $location.search({'parameter': null});
}

Answer 3

Using the $location service, you can remove the search param by assigning it a null value:

In the case when your parameter is null, in your case 'parameter' you can remove it from the url by assigning it a null value like;

$location.search('parameter', null);

Hope it helps.