How to open .xcodeproj programmatically?

Question

I have projects called A.xcodeproj, B.xcodeproj, C.xcodeproj

now what is question, in AppDelegate of Project A , open project B and C on condition.

int r         


        

Answer 1

on the command line use open to OPEN and SHOW xcode..
so in your case, when run == 0

when you want to BUILD the xcode project, invoke xcodebuild instead of open!..
so in your case, when run == 1