Is there a more efficient way of doing the following?
select *
from foo as a
where a.id = (select max(id) from foo where uid = a.uid group by uid)
if table is big in size. Make view
containing all last row id
create view lastrecords as (select max(id) from foo where uid = a.uid group by uid)
Now join your main query with this view
. It will be faster.
SELECT t1.* FROM tablename as t1
JOIN lastrecords as t2
ON t1.id = t2.id AND t1.uid = t2.uid;
OR You can do join with last records direct in query also:
SELECT t1.* FROM tablename as t1
JOIN (SELECT uid, MAX(id) id FROM tablename GROUP BY id) as t2
ON t1.id = t2.id AND t1.uid = t2.uid;
This code works on me:
SELECT * FROM foo GROUP BY foo.uid
HAVING MAX(foo.id)
This has worked for me thanks!
SELECT t1.* FROM foo t1
JOIN (SELECT uid, MAX(id) id FROM foo GROUP BY uid) t2
ON t1.id = t2.id AND t1.uid = t2.uid;
my version:
SELECT * FROM messages t1 JOIN (SELECT MAX(id) id FROM messages where uid = 8279 and actv=1 GROUP BY uid ) t2 ON t1.id = t2.id ORDER BY datex desc LIMIT 0,10;
this code below doesn't return all rows I want because if max id column is an inactive one then it skips the group even if the group has active rows..
select * from messages where uid = 8279 and actv=1 and id In (Select max(id) From messages Group By uid) order by datex desc;
The easiest way : you can select from selected list that is sorted.
SELECT * FROM (SELECT * FROM foo order by id DESC) AS footbl
group by uid
order by id DESC
Try this query -
SELECT t1.* FROM foo t1
JOIN (SELECT uid, MAX(id) id FROM foo GROUP BY uid) t2
ON t1.id = t2.id AND t1.uid = t2.uid;
Then use EXPLAIN to analyze queries.
SELECT t1.* FROM foo t1
LEFT JOIN foo t2
ON t1.id < t2.id AND t1.uid = t2.uid
WHERE t2.id is NULL;
Returning the last row of each GROUP BY
in MySQL with WHERE
clause:
SELECT *
FROM foo
WHERE id IN (
SELECT Max(id)
FROM foo
WHERE value='XYZ'
GROUP BY u_id
)
LIMIT 0,30