Really deleting nodes in XMLParser Object Groovy

Question

How to REALLY remove a node via XMLParser:

 x=\'\'\'

 
   a
   b
 
 

        

Answer 1

Removing nodes works pretty much like other DOM APIs. You have to pass the node you want to delete to the remove method of its parent.

Also the = operator is the assignment operator in Groovy. it.@C1 = 'a' would assign 'a' to the C1 attribute of each B node in the document. Since the result of that assignment is 'a', which is coerced to true by Groovy, find will always return the first node it encounters.

xml=new XmlParser().parseText(x)
def nodeToDel=xml.A.B.C1.find { it.text() == 'a' }
def parent = nodeToDel.parent()
parent.remove(nodeToDel)

Answer 2

Improving solution of Justin Piper, with a fully working example:

def xml = new XmlParser().parseText('''
    <root>
        <element id="10" />
        <element id="20" />
    </root>
''')
def nodeToDel = xml.find { it["@id"] == '20' }

if (nodeToDel) {
    nodeToDel.parent().remove(nodeToDel)
}

println xml