RSA decryption with a public key

后端 未结 1 2025
不知归路
不知归路 2021-02-06 16:53

I\'ve got some decryption problems in my Android project.

I\'m getting a string signed with a private key and I have to verify(decrypt) it with a public key. I\'d like to

相关标签:
1条回答
  • 2021-02-06 17:24

    Java has got the Java Cryptography Extension Framework, which is just designed for these things.

    BouncyCastle is a Cryptography Provider for this framework. This means, it provides your Java Cryptography Extension with implementations of cryptography algorithms.

    You'll find the basic classes for this in the packages java.security and javax.crypto

    To decrypt your message with a public key you could try the following:

    // Use RSA/NONE/NoPadding as algorithm and BouncyCastle as crypto provider
    Cipher asymmetricCipher = Cipher.getInstance("RSA/NONE/NoPadding", "BC");
    
    // asume, that publicKeyBytes contains a byte array representing
    // your public key
    X509EncodedKeySpec publicKeySpec = new X509EncodedKeySpec(publicKeyBytes);
    
    KeyFactory keyFactory;
    keyFactory = KeyFactory.getInstance(publicKeySpec.getFormat());
    Key key = keyFactory.generatePublic(publicKeySpec);
    
    // initialize your cipher
    asymmetricCipher.init(Cipher.DECRYPT_MODE, key);
    // asuming, cipherText is a byte array containing your encrypted message
    byte[] plainText = asymmetricCipher.doFinal(cipherText);
    

    Please note, that this example is very basic and lacks several try catch blocks. Also, you should not use an asymmetric cipher without padding as this makes you vulnerable to replay attacks. You may also encounter issues with the key length. In some Java packages, the maximum allowed key length is restricted. This may be solved by using the unlimited strength policy files.

    I hope, this helps you in getting started with the Java cryptography.

    0 讨论(0)
提交回复
热议问题