Replace a word with multiple lines using sed?

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礼貌的吻别
礼貌的吻别 2020-11-27 06:32

I\'m working on a bash-script that has to prepare an E-Mail for being sent to a user.

It aggregates some data, which ends up being multiple lines of stuff. For the e

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  • 2020-11-27 07:09

    I would suggest simply replacing sed with perl command like this:

    perl -i.bak -pe 's/_data_/$ENV{"DATA"}/g' mail.tpl 
    
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  • 2020-11-27 07:11

    You can do this with AWK using variable substitution. We can set a variable in AWK using -v, and then use AWK's gsub function to substitute all occurrences of a regular expression with that variable.

    For example, if the file test has the following contents ...

    foo
    bar
    blah _data_and_data_
    foo
    _data_ foobar _data_ again
    

    ... and the Bash variable $DATA is ...

    1
    2
    3
    4
    5
    

    ... then awk -v r=$DATA '{gsub(/_data_/,r)}1' test replaces all occurrences of the regular expression _data_ in the file test with the contents of $DATA, resulting in the following:

    foo
    bar
    blah 1
    2
    3
    4
    5and1
    2
    3
    4
    5
    foo
    1
    2
    3
    4
    5 foobar 1
    2
    3
    4
    5 again
    
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  • 2020-11-27 07:16

    ring bearer's answer didn't work for me; I think the usage of tr there is wrong, and the way it's written, it simply strips away newlines by use of echo.

    Instead, I used sed. I used code from another answer to replace newlines (credit: Zsolt Botykai). I also expected some dollar signs ($) in my input so I took care of that too. You might need to add other input handling. Note the use of double quotes in echo to preserve newlines.

    DATA="$(cat whatever)"
    ESCAPED_DATA="$(echo "${DATA}" | sed ':a;N;$!ba;s/\n/\\n/g' | sed 's/\$/\\$/g')"
    

    Then you can use ${ESCAPED_DATA} in sed:

    cat input | sed 's/one liner/'"${ESCAPED_DATA}"'/' > output 
    

    Just thought I'd share.

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