How to read multiple integer values from one line in Java using BufferedReader object?

Question

I am using BufferedReader class to read inputs in my Java program. I want to read inputs from a user who can enter multiple integer data in single line with space. I want to rea

Answer 1

i/p:34 54

 BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
                                                                        
 StringTokenizer st = new StringTokenizer(br.readLine()," ");
 for(int i=0;i<st.countTokens();i++){
   a=Integer.parseInt(st.nextToken());
   b=Integer.parseInt(st.nextToken());
 }

//For fast input output for one line

Answer 2

import java.io.*;
public class HelloWorld{

     public static void main(String []args){
        int i;
        System.out.println("enter the array element");
        InputStreamReader isr= new InputStreamReader();
        BufferedReader ib= new BufferedReader(isr);
        int a[]=new int [5];
        for(i=0;i<5;i++)
        {
            a[i]= Integer.parseInt(ib.readLine(a[i]));

        }
        for(i=0;i<5;i++)
        {
            System.out.println(a[i]);
        }

     }
}

Answer 3

You can use StringTokenizer class of java.util package. The StringTokenizer class allows an application to break a string into tokens. You can use this tokens using nextToken() method of StringTokenizer class.

You can use following constructor of StringTokenizer:

StringTokenizer(String str, String delimiter);

you can use space(" ") as delemeter.

int a[] = new int[N];
StringTokenizer st = new StringTokenizer(br.readLine() , " ");
for(int i=0 ; i<N ; i++) {
    a[i] = Integer.parseInt(st.nextToken());
}