Calculate the sequence : n!/ (1+1/2+1/3+…+1/n)

Question

Calculate the following sum 1!/1 + 2!/(1+1/2) + 3!/(1+1/2+1/3) + ... + n!/ (1+1/2+1/3+...+1/n), where n > 0.

public static double GetSumSix(int n)
    {