How to print colored text in Python?

前端 未结 30 2913
谎友^
谎友^ 2020-11-21 04:41

How can I output colored text to the terminal in Python?

相关标签:
30条回答
  • 2020-11-21 05:14

    This somewhat depends on what platform you are on. The most common way to do this is by printing ANSI escape sequences. For a simple example, here's some python code from the blender build scripts:

    class bcolors:
        HEADER = '\033[95m'
        OKBLUE = '\033[94m'
        OKCYAN = '\033[96m'
        OKGREEN = '\033[92m'
        WARNING = '\033[93m'
        FAIL = '\033[91m'
        ENDC = '\033[0m'
        BOLD = '\033[1m'
        UNDERLINE = '\033[4m'
    

    To use code like this, you can do something like

    print(bcolors.WARNING + "Warning: No active frommets remain. Continue?" + bcolors.ENDC)
    

    or, with Python3.6+:

    print(f"{bcolors.WARNING}Warning: No active frommets remain. Continue?{bcolors.ENDC}")
    

    This will work on unixes including OS X, linux and windows (provided you use ANSICON, or in Windows 10 provided you enable VT100 emulation). There are ansi codes for setting the color, moving the cursor, and more.

    If you are going to get complicated with this (and it sounds like you are if you are writing a game), you should look into the "curses" module, which handles a lot of the complicated parts of this for you. The Python Curses HowTO is a good introduction.

    If you are not using extended ASCII (i.e. not on a PC), you are stuck with the ascii characters below 127, and '#' or '@' is probably your best bet for a block. If you can ensure your terminal is using a IBM extended ascii character set, you have many more options. Characters 176, 177, 178 and 219 are the "block characters".

    Some modern text-based programs, such as "Dwarf Fortress", emulate text mode in a graphical mode, and use images of the classic PC font. You can find some of these bitmaps that you can use on the Dwarf Fortress Wiki see (user-made tilesets).

    The Text Mode Demo Contest has more resources for doing graphics in text mode.

    Hmm.. I think got a little carried away on this answer. I am in the midst of planning an epic text-based adventure game, though. Good luck with your colored text!

    0 讨论(0)
  • 2020-11-21 05:16

    I ended up doing this, I felt it was cleanest:

    formatters = {             
        'RED': '\033[91m',     
        'GREEN': '\033[92m',   
        'END': '\033[0m',      
    }
    
    print 'Master is currently {RED}red{END}!'.format(**formatters)
    print 'Help make master {GREEN}green{END} again!'.format(**formatters)
    
    0 讨论(0)
  • 2020-11-21 05:16

    note how well the with keyword mixes with modifiers like these that need to be reset (using Python 3 and Colorama):

    from colorama import Fore, Style
    import sys
    
    class Highlight:
      def __init__(self, clazz, color):
        self.color = color
        self.clazz = clazz
      def __enter__(self):
        print(self.color, end="")
      def __exit__(self, type, value, traceback):
        if self.clazz == Fore:
          print(Fore.RESET, end="")
        else:
          assert self.clazz == Style
          print(Style.RESET_ALL, end="")
        sys.stdout.flush()
    
    with Highlight(Fore, Fore.GREEN):
      print("this is highlighted")
    print("this is not")
    
    0 讨论(0)
  • 2020-11-21 05:18

    Try this simple code

    def prRed(prt): print("\033[91m {}\033[00m" .format(prt))
    def prGreen(prt): print("\033[92m {}\033[00m" .format(prt))
    def prYellow(prt): print("\033[93m {}\033[00m" .format(prt))
    def prLightPurple(prt): print("\033[94m {}\033[00m" .format(prt))
    def prPurple(prt): print("\033[95m {}\033[00m" .format(prt))
    def prCyan(prt): print("\033[96m {}\033[00m" .format(prt))
    def prLightGray(prt): print("\033[97m {}\033[00m" .format(prt))
    def prBlack(prt): print("\033[98m {}\033[00m" .format(prt))
    
    prGreen("Hello world")
    
    0 讨论(0)
  • 2020-11-21 05:19
    # Pure Python 3.x demo, 256 colors
    # Works with bash under Linux and MacOS
    
    fg = lambda text, color: "\33[38;5;" + str(color) + "m" + text + "\33[0m"
    bg = lambda text, color: "\33[48;5;" + str(color) + "m" + text + "\33[0m"
    
    def print_six(row, format, end="\n"):
        for col in range(6):
            color = row*6 + col - 2
            if color>=0:
                text = "{:3d}".format(color)
                print (format(text,color), end=" ")
            else:
                print(end="    ")   # four spaces
        print(end=end)
    
    for row in range(0, 43):
        print_six(row, fg, " ")
        print_six(row, bg)
    
    # Simple usage: print(fg("text", 160))
    

    Try it online

    0 讨论(0)
  • 2020-11-21 05:21

    You can use the Python implementation of the curses library: http://docs.python.org/library/curses.html

    Also, run this and you'll find your box:

    for i in range(255):
        print i, chr(i)
    
    0 讨论(0)
提交回复
热议问题