Firebase querying

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时光说笑
时光说笑 2021-02-06 12:53

Let\'s say I have a structure like this:

-users
  -user1_uid
    name
    distance
    age

How would I do a query like (Find users with distanc

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2条回答
  • 2021-02-06 13:05

    My first choice would be to query for all the users between 20 and 25 and then filter in code for ones with a distance < 100.

    The question states filtering in code is not an option but I wanted to include it for completeness for situations where it was several thousand nodes or less:

        struct User { //starting with a structure to hold user data
            var firebaseKey : String?
            var theAge: Int?
            var theDistance: Int?
        }
    
        var userArray = [User]() //the array of user structures
    
        usersRef.queryOrderedByChild("age").queryStartingAtValue(20)
         .queryEndingAtValue(25).observeEventType(.Value, withBlock: { snapshot in
    
            for child in snapshot.children { //.Value so iterate over nodes
    
                let age = child.value["age"] as! Int
                let distance = child.value["distance"] as! Int
                let fbKey = child.key!
    
                let u = User(firebaseKey: fbKey, theAge: age, theDistance: distance)
    
                userArray.append(u) //add the user struct to the array
            }
    
            //the array to contain the filtered users
            var filteredArray: [User] = []
            filteredArray = userArray.filter({$0.theDistance < 100}) //Filter it, baby!
    
            //print out the resulting users as a test.
            for aUser in filteredArray {
    
                let k = aUser.firebaseKey
                let a = aUser.theAge
                let d = aUser.theDistance
    
                print("array: \(k!)  \(a!)  \(d!)")
    
            }
    
        })
    }
    

    Now a potential super simple answer.

        let usersRef = self.myRootRef.childByAppendingPath("users")
    
        usersRef.queryOrderedByChild("age").queryStartingAtValue(20)
         .queryEndingAtValue(25).observeEventType(.ChildAdded, withBlock: { snapshot in
    
            let distance = snapshot.value["distance"] as! Int
    
            if distance < 100 {
                let age = snapshot.value["age"] as! Int
                let fbKey = snapshot.key!
    
                print("array: \(fbKey)  \(age)  \(distance)")
            }
        })
    

    Notice that we are leveraging .ChildAdded instead of .Value so each node is read in one at a time - if the distance is not what we want, we can ignore it and move on to the next.

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  • 2021-02-06 13:13

    Firebase can't combine always the conditions. How to query based on multiple conditions in Firebase?

    But, using the new firebase API, this post can give some hints: Query based on multiple where clauses in firebase

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