How to find the length of an char array in c

Question

I want to find the length of this :

char *s[]={\"s\",\"a\",\"b\"};

it should count 4 with the /0 but the strlen or sizeof(s)/sizeof(char) gives

Answer 1

What you have defined is not a string hence there is no NULL terminating character. Here you have declared pointers to 3 separate strings. BTW, you should declare your array as const char*.

Answer 2

strlen works if you terminate your array with null character. You cannot find number of elements in a char array unless you keep track of it. i.e store it in some variable like n. Every time you add member increment n and every time you remove decrement n

Answer 3

You are making an array of char* and not of char. That's why strlen won't work. Use

sizeof(s) / sizeof(char*) //should give 3

If you want a single string use

char s[] = "sab";

Answer 4

There is no direct way to determine the length of an array in C. Arrays in C are represented by a continuous block in a memory.

You must keep the length of the array as a separate value.

Answer 5

Why should it count 4? you have 3 pointers to char in this array, it should count 12 on most 32-bit platforms.

Answer 6

sizeof(s) / sizeof(s[0]) works no matter what type s contains.