Nested Set Query to retrieve all ancestors of each node

Question

I have a MySQL query that I thought was working fine to retrieve all the ancestors of each node, starting from the top node, down to its immediate node. However when I added a 5

Answer 1

First it's important to understand that you have an implicit GROUP BY

If you use a group function in a statement containing no GROUP BY clause, it is equivalent to grouping on all rows.

To make the point more understandable I'll leave out subqueries and reduce the problem to the banana. Banana is the set [10, 11]. The correct sorted ancestors are those:

SELECT "banana" as node, GROUP_CONCAT(title ORDER by `left`)
  FROM Tree WHERE `left` < 10 AND `right` > 11
  GROUP BY node;

The ORDER BY must be in GROUP_CONCAT() as you want the aggregation function to sort. ORDER BY outside sorts by the aggregated results (i.e. the result of GROUP_CONCAT()). The fact that it worked until level 4 is just luck. ORDER BY has no effect on an aggregate function. You would get the same results with or without the ORDER BY:

SELECT GROUP_CONCAT(title)
  FROM Tree WHERE `left` < 10 AND `right` > 11
  /* ORDER BY `left` */

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It might help to understand what SELECT GROUP_CONCAT(title ORDER BY left) FROM Tree WHERE … ORDER BY left does:

1. Get a selection (WHERE) which results in three rows in an undefined order:

   ("Food")
   ("Yellow")
   ("Fruit")
   

2. Aggregate the result into one row (implicit GROUP BY) in order to be able to use an aggregate function:

   (("Food","Yellow", "Fruit"))
   

3. Fire the aggregate function (GROUP_CONCAT(title, ORDER BY link)) on it. I.e. order by link and then concatenate:

   ("Food,Fruit,Yellow")
   

4. And now finally it sorts that result (ORDER BY). As it's only one row, sorting changes nothing.

   ("Food,Fruit,Yellow")
   

Answer 2

You can get the result using JOIN or SUB-QUERY.

Using JOIN:

SELECT t0.title node, GROUP_CONCAT(t2.title ORDER BY t2.left) ancestors 
FROM Tree t0
LEFT JOIN Tree t2 ON t2.left < t0.left AND t2.right > t0.right
GROUP BY t0.title; 

Check this SQL FIDDLE DEMO

Using SUB-QUERY:

SELECT t0.title node, 
      (SELECT GROUP_CONCAT(t2.title ORDER BY t2.left)
       FROM Tree t2 WHERE t2.left<t0.left AND t2.right>t0.right) ancestors
FROM Tree t0
GROUP BY t0.title;

Check this SQL FIDDLE DEMO

OUTPUT

|           NODE |             ANCESTORS |
|----------------|-----------------------|
|          Bacon |        Food,Meat,Pork |
| Bacon_Sandwich |  Food,Meat,Pork,Bacon |
|         Banana |     Food,Fruit,Yellow |
|           Beef |             Food,Meat |
|         Cherry |        Food,Fruit,Red |
|     Cherry_pie | Food,Fruit,Red,Cherry |
|           Food |                (null) |
|          Fruit |                  Food |
|           Meat |                  Food |
|           Pork |             Food,Meat |
|            Red |            Food,Fruit |
|         Yellow |            Food,Fruit |

In your sub query you had used ORDER BY after WHERE clause which won't affect the output. By default GROUP_CONCAT() function will orders the output string in ascending order of column value. It won't consider you explicit ORDER BY clause.

If you check your output of first query which returns the data in ascending order of title column. So the returned result for node Banana is Food,Fruit,Yellow.

But in your second result for Bacon_Sandwich is Bacon,Food,Meat,Pork because in ascending order Bacon comes first than Food will come.

If you want to order the result based on left column than you have to specify ORDER BY inside the GROUP_CONCAT() function as above. Check my both queries.

I prefer that you use JOIN instead of SUB-QUERY for improving performance.