Compare two time values in ios? [duplicate]

Answer 1

// Use compare method.

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
    [formatter setDateFormat:@"yyyy-MM-dd HH:mm:ss"];

    NSDate *startDate = [formatter dateFromString:@"2012-12-07 7:17:58"];
    NSDate *endDate = [formatter dateFromString:@"2012-12-07 7:17:59"];


    if ([startDate compare: endDate] == NSOrderedDescending) {
        NSLog(@"startDate is later than endDate");

    } else if ([startDate compare:endDate] == NSOrderedAscending) {
        NSLog(@"startDate is earlier than endDate");

    } else {
        NSLog(@"dates are the same");

    }

    // Way 2
    NSTimeInterval timeDifference = [endDate timeIntervalSinceDate:startDate];

    double minutes = timeDifference / 60;
    double hours = minutes / 60;
    double seconds = timeDifference;
    double days = minutes / 1440;

    NSLog(@" days = %.0f,hours = %.2f, minutes = %.0f,seconds = %.0f", days, hours, minutes, seconds);

    if (seconds >= 1)
        NSLog(@"End Date is grater");
    else
        NSLog(@"Start Date is grater");

Answer 2

Use the following code to do the convert from the nsstring to nsdate and compare them.

NSString *time1 = @"08:15:12";
NSString *time2 = @"18:12:08";

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"HH:mm:ss"];

NSDate *date1= [formatter dateFromString:time1];
NSDate *date2 = [formatter dateFromString:time2];

NSComparisonResult result = [date1 compare:date2];
if(result == NSOrderedDescending)
{
    NSLog(@"date1 is later than date2"); 
}
else if(result == NSOrderedAscending)
{
    NSLog(@"date2 is later than date1"); 
}
else
{
    NSLog(@"date1 is equal to date2");
}

Answer 3

First you need to convert your time string to NSDate => Converting time string to Date format iOS.

Then use following code

NSDate *timer1 =...
NSDate *timer2 =...

       NSComparisonResult result = [timer1 compare:timer2];
       if(result == NSOrderedDescending)
       {
          // time 1 is greater then time 2 
       }
       else if(result == NSOrderedAscending)
       {
           // time 2 is greater then time 1 
       }
       else
       {
          //time 1 is equal to time 2
       }

Answer 4

You can use this link

According to Apple documentation of NSDate compare:

Returns an NSComparisonResult value that indicates the temporal ordering of the receiver and another given date.

- (NSComparisonResult)compare:(NSDate *)anotherDate

Parameters anotherDate

The date with which to compare the receiver. This value must not be nil. If the value is nil, the behavior is undefined and may change in future versions of Mac OS X.

Return Value

If:

The receiver and anotherDate are exactly equal to each other, NSOrderedSame

The receiver is later in time than anotherDate, NSOrderedDescending

The receiver is earlier in time than anotherDate, NSOrderedAscending

In other words:

if ([date1 compare:date2]==NSOrderedSame) ...

Note that it might be easier to read and write this :

if ([date2 isEqualToDate:date2]) ...

See Apple Documentation about this one. If you feel any problem you can also use this link here. Here you can go through Nelson Brian answer.

I have done this at my end as follows-

NSDate  * currentDateObj=@"firstDate";
NSDate  * shiftDateFieldObj=@"SecondDate";


NSTimeInterval timeDifferenceBetweenDates = [shiftDateFieldObj timeIntervalSinceDate:currentDateObj];

You can also get time interval according to time difference between dates. Hope this helps.