function with multiple arguments

Question

how to pass multiple arguments in a single function in Objective-C? I want to pass 2 integer values and the return value is also integer. I want to use the new Objective-C synta

Answer 1

Like this:

int sum(int a, int b) {
    return a + b;
}

Called like this:

int result;
result = sum(3, 5);
// result is now 8

More here

Answer 2

Since this is still google-able and there are better solutions than the accepted answer; there's no need for the hideous withArg2 – just use colons:

Declaration:

@interface
-(void) setValues: (int)v1 : (int)v2;

Definition:

@implementation
-(void) setValues: (int)v1 : (int)v2 {
    //do something with v1 and v2
}

Answer 3

In objective-c it is really super easy. Here is the way you would do it in C:

int functName(int arg1, int arg2) 
{
    // Do something crazy!
    return someInt;
}

This still works in objective-c because of it's compatibility with C, but the objective-c way to do it is:

// Somewhere in your method declarations:
- (int)methodName:(int)arg1 withArg2:(int)arg2
{
    // Do something crazy!
    return someInt;
}

// To pass those arguments to the method in your program somewhere:
[objectWithOurMethod methodName:int1 withArg2:int2];

Best of luck!

Answer 4

int add (int a, int b)
{
    int c;
    c = a + b;
   return c;
}

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