I am currently using a JSON encoded array to display the users in my database for an auto-suggest feature.
It looks something like this:
$sth = mysql_que
Try in this way:-
$temp = json_encode($json); //$json={"var1":"value1","var2":"value2"}
$temp=substr($temp,0,-1);
$temp.=',"variable":"'.$value.'"}';
Just keep pushing to the $data
array.
$json = array();
while($row = mysql_fetch_assoc($sth)) {
$json['name'] = $row['name'];
$json['id'] = $row['id'];
$data[] = $json;
}
$custom = array('name'=>'foo', 'id' => 'bar');
$data[] = $custom;
Then at the very end, do your json_encode
. Assuming you're not referring to merging it in the JS itself with multiple ajax calls.
And if you have separate scripts, combine them in one php page.
You could edit the JSON (text), but it's much easier to modify the array before you encode it. Or am I missing something?
I'm not an expert in any of these fields, but I'll try and see if I can help. Try one of these:
Option 1 (I don't know how unions work in mysql):
$sth = mysql_query("SELECT id, name FROM users union SELECT id, name FROM (SELECT id, title as name from another_table) as T2");
$json = array();
while($row = mysql_fetch_assoc($sth)) {
$json['name'] = $row['name'];
$json['id'] = $row['id'];
}
$json['name'] = 'A new name';
$json['id'] = '444';
$data[] = $json;
print json_encode($data);
I've never done PHP, so I'm making assumptions. I've also never used MySql, so there's more assumptions.
Option 2:
$sth = mysql_query("SELECT id, name FROM users");
$json = array();
while($row = mysql_fetch_assoc($sth)) {
$json['name'] = $row['name'];
$json['id'] = $row['id'];
}
$sth = mysql_query("SELECT id, title from another_table");
while($row = mysql_fetch_assoc($sth)) {
$json['name'] = $row['title'];
$json['id'] = $row['id'];
}
$json['name'] = 'A new name';
$json['id'] = '444';
$data[] = $json;
print json_encode($data);
Hope this helps.