Array operations with n-dimensional array using LINQ (C#)

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温柔的废话
温柔的废话 2021-02-06 03:23

Assume we have a jagged array

int[][] a = { new[] { 1, 2, 3, 4 }, new[] { 5, 6, 7, 8 }, new[] { 9, 10, 11, 12 } };

To get a sum of second row a

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  • 2021-02-06 03:42

    About your question "How to use LINQ methods with n-dimensional arrays":

    You can't use most LINQ methods with a n dimensional array, because such an array only implements IEnumerable but not IEnumerable<T> and most of the LINQ extension methods are extension methods for IEnumerable<T>.

    About the other question: See dtb's answer.

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  • 2021-02-06 03:47

    To add to dtb's solution, a more general way of iterating over all items of the array would be:

    int[,] b = { { 1, 2, 3, 4 }, { 5, 6, 7, 8 }, { 9, 10, 11, 12 } };
    
    var flattenedArray = Enumerable.Range(0, b.GetLength(0))
                         .SelectMany(i => Enumerable.Range(0, b.GetLength(1))
                             .Select(j => new { Row = i, Col = j }));
    

    And now:

    var rowSum2 = flattenedArray.Where(t => t.Row == 1).Sum(t => b[t.Row, t.Col]);
    var colSum2 = flattenedArray.Where(t => t.Col == 1).Sum(t => b[t.Row, t.Col]);
    

    Of course this is ultra-wasteful as we are creating coordinate tuples even for those items that we will end up filtering out with Where, but if you don't know what the selection criteria will be beforehand this is the way to go (or not -- this seems more like an excercise than something you 'd want to do in practice).

    I can also imagine how this might be extended for arrays of any rank (not just 2D) using a recursive lambda and something like Tuple, but that crosses over into masochism territory.

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  • 2021-02-06 03:47

    The simplest LINQ only approach I can see to do these kinds of row and column operations on a two dimensional array is to define the following lookups:

    var cols = a
        .OfType<int>()
        .Select((x, n) => new { x, n, })
        .ToLookup(xn => xn.n % a.GetLength(1), xn => xn.x);
    
    var rows = a
        .OfType<int>()
        .Select((x, n) => new { x, n, })
        .ToLookup(xn => xn.n / a.GetLength(1), xn => xn.x);
    

    Now you can simply do this:

    var firstColumnSum = cols[0].Sum();
    

    As for n-dimensional, it just gets too painful... Sorry.

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  • 2021-02-06 03:51

    LINQ to Objects is based on the IEnumerable<T> Interface, i.e. a one-dimensional sequence of values. This means it doesn't mix well with n-dimensional data structures like non-jagged arrays, although it's possible.

    You can generate one-dimensional sequence of integers that index into the n-dimensional array:

    int rowSum = Enumerable.Range(0, a.GetLength(1)).Sum(i => a[1, i]);
    
    int colSum = Enumerable.Range(0, a.GetLength(0)).Sum(i => a[i, 1]);
    
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  • 2021-02-06 03:54

    A simpler way is doing like below

     var t = new List<Tuple<int, int>>();
     int[][] a = t.Select(x => new int[]{ x.Item1, x.Item2}).ToArray(); 
    
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  • 2021-02-06 04:01

    The 2D array doesn't have any built in way of iterating over a row or column. It's not too difficult to create your own such method though. See this class for an implementation which gets an enumerable for row and column.

    public static class LINQTo2DArray
    {
        public static IEnumerable<T> Row<T>(this T[,] Array, int Row)
        {
            for (int i = 0; i < Array.GetLength(1); i++)
            {
                yield return Array[Row, i];
            }
        }
        public static IEnumerable<T> Column<T>(this T[,] Array, int Column)
        {
            for (int i = 0; i < Array.GetLength(0); i++)
            {
                yield return Array[i, Column];
            }
        }
    }
    

    You can also flatten the array usinga.Cast<int>() but you would then loose all the info about columns/rows

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