how to get POST data in django 1.3

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Hey, I am following this tutorial to learn to make a wiki page with Django. However, it is made in django 0.96 and I use Django 1.3 so there are some things that are different.

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4条回答

青春惊慌失措

2021-02-06 03:34

I guess you've missed the symbol '=' in the form declaration.

action"/wikicamp/{{page_name}}/save/"

action="/wikicamp/{{page_name}}/save/"

Fortunately, it might be not a mistake. So if it is not a solution, try some more easy example:

# settings.py

TEMPLATE_DIRS = (
    # Here comes something like "C:/www/django/templates"
)

MIDDLEWARE_CLASSES = (
    ...
    'django.middleware.csrf.CsrfViewMiddleware',
    ...
)

# urls.py

urlpatterns = patterns('',
    ('^foo', foo),
)


# views.py
from django.http import HttpResponse
from django.shortcuts import render_to_response
from django.core.context_processors import csrf

def foo(request):
    d = {}
    d.update(csrf(request))
    if 'output' in request.POST:
        d.update({'output':request.POST['output']})
    return render_to_response('foo.html',d)

# foo.html template
<html>
<h1> Foo </h1>
<form action="/foo" method = "post">
    {% csrf_token %}
    <input type="text" name="output"></input>
    <input type="submit" value="go"></input>
</form>
<p> Output: {{ output }} </p>
</html>

Hope this will work

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执笔经年

2021-02-06 03:38

You've got to include {% csrf_token %} in your form's template between your <form> tags.

<form method="post" action"/wikicamp/{{page_name}}/save/">
    {% csrf_token %}
    <textarea name="content" rows="20" cols="60">{{content}}</textarea><br>
    <input type="submit" value="Save Page"/>
</form>

If the csrf_token is not rendered into your form make sure you're providing the RequestContext in the view's response:

from django.shortcuts import render_to_response
from django.template import RequestContext

def app_view(request):
    return render_to_response('app_template.html', 
                              app_data_dictionary, 
                              context_instance=RequestContext(request))

Or, use this shortcut method:

from django.views.generic.simple import direct_to_template

def app_view(request):             
    return direct_to_template(request, 'app_template.html', app_data_dictionary)

The RequestContext is always available when you're using generic views.

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萌比男神i

2021-02-06 03:43

You will need the {% csrf_token %} template tag in between your tags as well as including

   django.middleware.csrf.CsrfViewMiddleware
   django.middleware.csrf.CsrfResponseMiddleware

in your MIDDLEWARE_CLASSES in the applications settings.py

Adding some example post data handling:

This is an example of one of the times I am using POST data in a view. I will generally rely on the form class to do verification via the cleaned_data array.

if request.method == 'POST':
        form = ForgotPassword(data=request.POST)
        if form.is_valid():
            try:
                new_user = backend.forgot_password(request, **form.cleaned_data)
            except IntegrityError:
                context = {'form':form}
                form._errors[''] = ErrorList(['It appears you have already requested a password reset, please \
                check ' + request.POST['email2'] + ' for the reset link.'])
                return render_template(request,'passwordReset/forgot_password.html',context)
            if success_url is None:
                to, args, kwargs = backend.post_forgot_password(request, new_user)
                return redirect(to, *args, **kwargs)
            else:
                return redirect(success_url)

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轮回少年

2021-02-06 03:43

re above use "request.POST" not "c.POST" in the 3rd line

def save_page (request,page_name):
    content = request.POST["content"]

and change in "edit_page"

-   return render_to_response("edit.html",{"page_name":page_name, "content":content})
+   t = get_template('edit.html')
+   html = t.render(Context({"page_name":page_name, "content":content}))
+   return HttpResponse(html)

- :remove 
+ :add

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