Populate a Drop down box from a mySQL table in PHP

Question

I am trying to populate a Drop down box from results of a mySQL Query, in Php. I\'ve looked up examples online and I\'ve tried them on my webpage, but for some reason they j

Answer 1

You will need to make sure that if you're using a test environment like WAMP set your username as root. Here is an example which connects to a MySQL database, issues your query, and outputs <option> tags for a <select> box from each row in the table.

<?php

mysql_connect('hostname', 'username', 'password');
mysql_select_db('database-name');

$sql = "SELECT PcID FROM PC";
$result = mysql_query($sql);

echo "<select name='PcID'>";
while ($row = mysql_fetch_array($result)) {
    echo "<option value='" . $row['PcID'] . "'>" . $row['PcID'] . "</option>";
}
echo "</select>";

?>

Answer 2

Below is the code for drop down using MySql and PHP:

<?
$sql="Select PcID from PC"
$q=mysql_query($sql)
echo "<select name=\"pcid\">"; 
echo "<option size =30 ></option>";
while($row = mysql_fetch_array($q)) 
{        
echo "<option value='".$row['PcID']."'>".$row['PcID']."</option>"; 
}
echo "</select>";
?>

Answer 3

No need to do this:

while ($row = mysqli_fetch_array($result)) {
    $rows[] = $row;
}

You can directly do this:

while ($row = mysqli_fetch_array($result)) {
        echo "<option value='" . $row['value'] . "'>" . $row['value'] . "</option>";
    }

Answer 4

What if you want to use both id and name in the dropdown? Here is the code for that:

$mysqli = new mysqli($servername, $username, $password, $dbname);
$sqlSelect = "SELECT BrandID, BrandName FROM BrandMaster";
$result = $mysqli -> query ($sqlSelect);

echo "<select id='brandId' name='brandName'>";

while ($row = mysqli_fetch_array($result)) {
   unset($id, $name);
   $id = $row['BrandID'];
   $name = $row['BrandName']; 
   echo '<option value="'.$id.'">'.$name.'</option>';
 }
 echo "</select>";

Answer 5

Since mysql_connect has been deprecated, connect and query instead with mysqli:

$mysqli = new mysqli("hostname","username","password","database_name");
$sqlSelect="SELECT your_fieldname FROM your_table";
$result = $mysqli -> query ($sqlSelect);

And then, if you have more than one option list with the same values on the same page, put the values in an array:

while ($row = mysqli_fetch_array($result)) {
    $rows[] = $row;
}

And then you can loop the array multiple times on the same page:

foreach ($rows as $row) {
    print "<option value='" . $row['your_fieldname'] . "'>" . $row['your_fieldname'] . "</option>";
}

Answer 6

At the top first set up database connection as follow:

<?php
$mysqli = new mysqli("localhost", "username", "password", "database") or die($this->mysqli->error);
$query= $mysqli->query("SELECT PcID from PC");
?> 

Then include the following code in HTML inside form

<select name="selected_pcid" id='selected_pcid'>

            <?php 

             while ($rows = $query->fetch_array(MYSQLI_ASSOC)) {
                        $value= $rows['id'];
                ?>
                 <option value="<?= $value?>"><?= $value?></option>
                <?php } ?>
             </select>

However, if you are using materialize css or any other out of the box css, make sure that select field is not hidden or disabled.