How would I get the height and width of a video from ffmpeg
\'s information output. For example, with the following output:
$ ffmpeg -i video.mp4
In this blog post theres a rough solution in python:
import subprocess, re
pattern = re.compile(r'Stream.*Video.*([0-9]{3,})x([0-9]{3,})')
def get_size(pathtovideo):
p = subprocess.Popen(['ffmpeg', '-i', pathtovideo],
stdout=subprocess.PIPE,
stderr=subprocess.PIPE)
stdout, stderr = p.communicate()
match = pattern.search(stderr)
if match:
x, y = map(int, match.groups()[0:2])
else:
x = y = 0
return x, y
This however assumes it's 3 digits x 3 digits (i.e. 854x480), you'll need to loop through the possible dimension lengths, such as (1280x720):
possible_patterns = [re.compile(r'Stream.*Video.*([0-9]{4,})x([0-9]{4,})'), \
re.compile(r'Stream.*Video.*([0-9]{4,})x([0-9]{3,})'), \
re.compile(r'Stream.*Video.*([0-9]{3,})x([0-9]{3,})')]
and check if match returns None on each step:
for pattern in possible_patterns:
match = pattern.search(stderr)
if match!=None:
x, y = map(int, match.groups()[0:2])
break
if match == None:
print "COULD NOT GET VIDEO DIMENSIONS"
x = y = 0
return '%sx%s' % (x, y)
Could be prettier, but works.
BAD (\d+x\d+)
$ echo 'Stream #0:0(eng): Video: mjpeg (jpeg / 0x6765706A), yuvj420p, 1280x720, 19939 kb/s, 30 fps, 30 tbr, 30 tbn, 30 tbc' | perl -lane 'print $1 if /(\d+x\d+)/'
> 0x6765706
GOOD ([0-9]{2,}x[0-9]+)
$ echo 'Stream #0:0(eng): Video: mjpeg (jpeg / 0x6765706A), yuvj420p, 1280x720, 19939 kb/s, 30 fps, 30 tbr, 30 tbn, 30 tbc' | perl -lane 'print $1 if /([0-9]{2,}x[0-9]+)/'
> 1280x720
From Fredrik's tip above, here is how I did it using MediaInfo ( http://mediainfo.sourceforge.net/en ):
>>> p1 = subprocess.Popen(['mediainfo', '--Inform=Video;%Width%x%Height%',
'/Users/david/Desktop/10stest720p.mov'],stdout=PIPE)
>>> dimensions=p1.communicate()[0].strip('\n')
>>> dimensions
'1280x688'
without re module
out = error_message.split() # make a list from resulting error string
out.reverse()
for index, item in enumerate(out): # extract the item before item= "[PAR"
if item == "[PAR": #
dimension_string = out[i+1] #
video_width, video_height = dimension_string.split("x")
Edit: not a good answer because not all videos have that "PAR" information :(
As mentioned here, ffprobe
provides a way of retrieving data about a video file. I found the following command useful ffprobe -v quiet -print_format json -show_streams input-video.xxx
to see what sort of data you can checkout.
I then wrote a function that runs the above command and returns the height and width of the video file:
import subprocess
import shlex
import json
# function to find the resolution of the input video file
def findVideoResolution(pathToInputVideo):
cmd = "ffprobe -v quiet -print_format json -show_streams"
args = shlex.split(cmd)
args.append(pathToInputVideo)
# run the ffprobe process, decode stdout into utf-8 & convert to JSON
ffprobeOutput = subprocess.check_output(args).decode('utf-8')
ffprobeOutput = json.loads(ffprobeOutput)
# find height and width
height = ffprobeOutput['streams'][0]['height']
width = ffprobeOutput['streams'][0]['width']
return height, width
Have a look at mediainfo Handles most of the formats out there.
If you looking for a way to parse the output from ffmpeg, use the regexp \d+x\d+
Example using perl:
$ ./ffmpeg -i test020.3gp 2>&1 | perl -lane 'print $1 if /(\d+x\d+)/'
176x120
Example using python (not perfect):
$ ./ffmpeg -i /nfshome/enilfre/pub/test020.3gp 2>&1 | python -c "import sys,re;[sys.stdout.write(str(re.findall(r'(\d+x\d+)', line))) for line in sys.stdin]"
[][][][][][][][][][][][][][][][][][][]['176x120'][][][]
Python one-liners aren't as catchy as perl ones :-)