I like the datastore simplicity, scalability and ease of use; and the enhancements found in the new ndb library are fabulous.
As I understand datastore best practices, o
Maybe just aim for this style of paging:
(first)(Prev)(Page1)(Page2)(Page3)....(Last)(next)
That way the total number is not required - you only need your code to know that there is enough results for another 3+ pages. with page size of 10 items per page, you just need to know there are 30+ items.
If you have 60 items, (enough for 6 pages) when youre already on page 4, your code would look forward and realise there are only another 20 records to go, so you could then show the last page number:
(first)(Prev)(Page4)(Page5)(Page6)(next)(last)
Basically for each fetch for the current page, just fetch enough records for another 3 pages of data, count them to see how many more pages you actully have, then dispaly your pager accordingly.
Also, if you just fetch the keys, it will be more efficient than fetching extra items. hope that makes some sense!!?? :)
It all depends on how many results you typically get. E.g. by passing .count() a suitable limit you can provide an exact count if the #items is e.g. <= 100 and "many" if there are more. It sounds like you cannot pre-compute all possible counts, but at least you could cache them, thereby saving many datastore ops.
Using NDB, the most efficient approach may either be to request the first page of entities using fetch_page(), and then using the resulting cursor as a starting point for a count() call; or alternatively, you may be better off running the fetch() of the first page and the count() concurrently using its async facilities. The second option may be your only choice if your query does not support cursors. Most IN / OR queries don't currently support cursors, but they do if you order by __key__
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In terms of UI options, I think it's sufficient to offer next and previous page options; the "Gooooooogle" UI that affords skipping ahead several pages is cute but I almost never use it myself. (To implement "previous page", reverse the order of the query and use the same cursor you used for the current page. I'm pretty sure this is guaranteed to work.)
Since the question was "looking for ideas/alternatives to providing a page", maybe the very simple alternative of fetching 10 pages worth of key_only items, then handling navigation through within this set is worth considering.
I have elaborated on this in answering a similar question, you will find sample code there :
Backward pagination with cursor is working but missing an item
The sample code would be more appropriate for this question. Here is a piece of it:
def session_list():
page = request.args.get('page', 0, type=int)
sessions_keys = Session.query().order(-Session.time_opened).fetch(100, keys_only=True)
sessions_keys, paging = generic_list_paging(sessions_keys, page)
# generic_list_paging will select the proper sublist.
sessions = [ sk.get() for sk in sessions_keys ]
return render_template('generic_list.html', objects=sessions, paging=paging)
See the referenced question for more code.
Of course, if the result set is potentially huge, some limit to the fetch must still be given, the hard limit being 1000 items I think. Obviously, it the result is more than some 10 pages long, the user will be asked to refine by adding criteria.
Dealing with paging within a few hundreds of keys_only items is really so much simpler, that it's definitely worth considering. It makes it quite easy to provide direct page navigation as mentionned in the question. The actual entity items are only fetched for the actual current page, the rest is only keys so it's not so costly. And you may consider keeping the keys_only result set in memcache for a few minutes so that a user quickly browsing through pages will not require the same query to be performed again.