I\'m aware that you can remove keys from a jsonb in postgres using something like this
select \'{\"a\": 1, \"b\": 2, \"c\":3}\'::jsonb -\'a\';
?column?
--------
If you want to filter multiple rows with JSONB documents in each of them:
-- Let's generate rows with JSONB column:
WITH s AS (SELECT generate_series(1, 100) num),
g AS (SELECT num, jsonb_build_object('a', s.num, 'b', s.num * 2) obj FROM s),
-- A "filter" adding (in my example only keys of "filter" document remain in result rows)
j AS (SELECT '{"a": "int", "c": "string"}'::jsonb AS filter),
a AS (SELECT (ARRAY(SELECT jsonb_object_keys(filter))) AS ar FROM j),
-- Useless keys removing
o AS (SELECT jsonb_object_agg(l.key, l.value) obj
FROM g, LATERAL jsonb_each(g.obj) l, a
WHERE l.key = ANY(a.ar)
GROUP BY num)
SELECT * FROM o ORDER BY obj->'a';
You can get just the value like so:
select '{"a": 1, "b": 2}'::jsonb-> 'a';
If you must, you can transform that back into jsonb manually, or perhaps go through an array, hstore or other intermediate type. Here's the "manual" way
select ('{ "a": '||('{"a": 1, "b": 2}'::jsonb->'a')::text||'}')::jsonb
You can do this
SELECT jsonb_column->>'key_name_here' as 'column_name_of_your_own' from table_name
In the case of the query asked above, it would be
select '{"a": 1, "b": 2, "c":3}'::jsonb->>'a'
You can filter down to a single key fairly easily like so:
jsonb_object(ARRAY[key, jsonb_data -> key])
...or you can filter down to multiple keys:
(SELECT jsonb_object_agg(key, value) FROM jsonb_each(jsonb_data) WHERE key IN ('a', 'b'))
Or on a more complex condition, if you want:
(
SELECT jsonb_object_agg(key, value)
FROM jsonb_each(jsonb_data)
WHERE
key NOT LIKE '__%'
AND jsonb_typeof(value) != 'null'
)
These kinds of questions can be answered very easily by simply reading the documentation.
I actually found that this way works to.
select jsonb_build_object('key', column->'key') from table;
reference: https://www.reddit.com/r/PostgreSQL/comments/73auce/new_user_to_postgres_can_i_grab_multiple_keys_of/