Here\'s a very simple way to build an suffix array from a string in python:
def sort_offsets(a, b):
return cmp(content[a:], content[b:])
content = \"foobar
The buffer function does not copy the whole string, but creates an object that only references the source string. Using interjay's suggestion, that would be:
suffix_array.sort(key=lambda a: buffer(content, a))
+1 for a very interesting problem! I can't see any obvious way to do this directly, but I was able to get a significant speedup (an order of magnitude for 100000 character strings) by using the following comparison function in place of yours:
def compare_offsets2(a, b):
return (cmp(content[a:a+10], content[b:b+10]) or
cmp(content[a:], content[b:]))
In other words, start by comparing the first 10 characters of each suffix; only if the result of that comparison is 0, indicating that you've got a match for the first 10 characters, do you go on to compare the entire suffices.
Obviously 10 could be anything: experiment to find the best value.
This comparison function is also a nice example of something that isn't easily replaced with a key function.
You could use the blist extension type that I wrote. A blist
works like the built-in list
, but (among other things) uses copy-on-write so that taking a slice takes O(log n) time and memory.
from blist import blist
content = "foobar baz foo"
content = blist(content)
suffix_array = range(len(content))
suffix_array.sort(key = lambda a: content[a:])
print suffix_array
[6, 10, 4, 8, 3, 7, 11, 0, 13, 2, 12, 1, 5, 9]
I was able to create a suffix_array from a randomly generated 100,000-character string in under 5 seconds, and that includes generating the string.
I don't know if there's a fast way to compare substrings, but you can make your code much faster (and simpler) by using key
instead of cmp
:
suffix_array.sort(key=lambda a: content[a:])
This will create the substring just once for each value of a.
Edit: A possible downside is that it will require O(n^2) memory for the substrings.