Python: convert string to byte array

Question

Say that I have a 4 character string, and I want to convert this string into a byte array where each character in the string is translated into its hex equivalent. e.g.

Answer 1

Just use a bytearray() which is a list of bytes.

Python2:

s = "ABCD"
b = bytearray()
b.extend(s)

Python3:

s = "ABCD"
b = bytearray()
b.extend(map(ord, s))

By the way, don't use str as a variable name since that is builtin.

Answer 2

An alternative to get a byte array is to encode the string in ascii: b=s.encode('ascii').

Answer 3

This works for me (Python 2)

s = "ABCD"
b = bytearray(s)

# if you print whole b, it still displays it as if its original string
print b

# but print first item from the array to see byte value
print b[0]

Reference: http://www.dotnetperls.com/bytes-python

Answer 4

encode function can help you here, encode returns an encoded version of the string

In [44]: str = "ABCD"

In [45]: [elem.encode("hex") for elem in str]
Out[45]: ['41', '42', '43', '44']

or you can use array module

In [49]: import array

In [50]: print array.array('B', "ABCD")
array('B', [65, 66, 67, 68])

Answer 5

This work in both Python 2 and 3:

>>> bytearray(b'ABCD')
bytearray(b'ABCD')

Note string started with b.

To get individual chars:

>>> print("DEC HEX ASC")
... for b in bytearray(b'ABCD'):
...     print(b, hex(b), chr(b))
DEC HEX ASC
65 0x41 A
66 0x42 B
67 0x43 C
68 0x44 D

Hope this helps

Answer 6

s = "ABCD"
from array import array
a = array("B", s)

If you want hex:

print map(hex, a)