How to increment a value with leading zeroes?

Question

What would be the best way to increment a value that contains leading zeroes? For example, I\'d like to increment \"00000001\". However, it should be noted that the number of

Answer 1

Determine the length, convert it to an integer, increment it, then convert it back to a string with leading zeros so that it has the same length as before.

Answer 2

int('00000001') + 1

if you want the leading zeroes back:

"%08g" % (int('000000001') + 1)

Answer 3

Presumably, you specifically mean an integer represented as a string with leading zeros?

If that's the case, I'd do it thusly:

>>> a
'00000000000000099'
>>> l = len(a)
>>> b = int(a)+1
>>> b
100
>>> ("%0"+"%dd" % l) % b
'00000000000000100'

Answer 4

Use the much overlooked str.zfill():

str(int(x) + 1).zfill(len(x))

Answer 5

"%%0%ii" % len(x) % (int(x)+1)

-- MarkusQ

P.S. For x = "0000034" it unfolds like so:

"%%0%ii" % len("0000034") % (int("0000034")+1)
"%%0%ii" % 7 % (34+1)
"%07i" % 35
"0000035"

Answer 6

"my code is in c" int a[6]={0,0,0,0,0,0},i=5,k,p; while(a[0]!=10) { do { for(p=0;p<=i;p++) printf("%d",a[p]); printf("\n"); delay(100); a[i]++; }while(a[i]!=10); for(k=0;k<=i;k++) if(a[i-k]==10) { a[i-(k+1)]++; a[i-k]=0; } }