Calculate business hours between two dates

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How can I calculate business hours between two dates? For example we have two dates; 01/01/2010 15:00 and 04/01/2010 12:00 And we have working hours 09:00 to 17:00 in weekda

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14条回答

北荒

2020-11-27 05:26

Another way of thinking, the below function work correctly if your first day of week is Monday otherwise you should change related lines including (6,7) to your local weekend's days

create function fn_worktime(@Datetime1 DateTime,@Datetime2 DateTime)
Returns BigInt
as
Begin
    Declare 
            @Date1 Date, 
            @Date2 Date,
            @DateIndex Date,
            @minutes int,
            @lastDayMinutes int,
            @StartTime int , --in minutes
            @FinishTime int ,--in minutes
            @WorkDayLong int --in minutes

    Set @StartTime  =8 * 60 + 30 -- 8:30
    Set @FinishTime =17* 60 + 30 -- 17:30
    Set @WorkDayLong =@FinishTime - @StartTime  

    Set @Date1 = Convert(Date,@DateTime1)
    Set @Date2 = Convert(Date,@DateTime2)
    Set @minutes=DateDiff(minute,@DateTime1,DateAdd(MINUTE,@FinishTime ,convert(DateTime,@Date1)))
    if @minutes<0 OR DatePart(dw,@Date1) in (6,7)  -- you can even check holdays here. '(6 Saturday,7 Sunday) according to SET DATEFIRST 1'
        Set @minutes=0

    Set @DateIndex=DateAdd(day,1,@Date1)
    While @DateIndex<@Date2
    Begin
        if DatePart(dw,@DateIndex) not in (6,7)  -- you can even check holdays here. '(6 Saturday,7 Sunday) according to SET DATEFIRST 1'
            set @minutes=@minutes+@WorkDayLong 
        Set @DateIndex=DateAdd(day,1,@DateIndex)
    End
    if DatePart(dw,@DateIndex) not in (6,7)  -- you can even check holdays here
    Begin
        set @lastDayMinutes=DateDiff(minute,DateAdd(MINUTE ,@StartTime ,convert(DateTime,@Date2)),@DateTime2)
        if @lastDayMinutes>@WorkDayLong 
            set @lastDayMinutes=@WorkDayLong 
        if @Date1<>@Date2   
            set @minutes=@minutes+@lastDayMinutes
        Else
            Set @minutes=@minutes+@lastDayMinutes-@WorkDayLong 

    End
    return @minutes
End

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庸人自扰

2020-11-27 05:29

I have actually done this before, taking into account all the variables (weekends, holidays, etc) for business hours is very difficult, I think this task is best done outside SQL

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情书的邮戳

2020-11-27 05:30

Baran's answer fixed and modified for SQL 2005

SQL 2008 and above:

-- =============================================
-- Author:      Baran Kaynak (modified by Kodak 2012-04-18)
-- Create date: 14.03.2011
-- Description: 09:30 ile 17:30 arasındaki iş saatlerini hafta sonlarını almayarak toplar.
-- =============================================
CREATE FUNCTION [dbo].[WorkTime] 
(
    @StartDate DATETIME,
    @FinishDate DATETIME
)
RETURNS BIGINT
AS
BEGIN
    DECLARE @Temp BIGINT
    SET @Temp=0

    DECLARE @FirstDay DATE
    SET @FirstDay = CONVERT(DATE, @StartDate, 112)

    DECLARE @LastDay DATE
    SET @LastDay = CONVERT(DATE, @FinishDate, 112)

    DECLARE @StartTime TIME
    SET @StartTime = CONVERT(TIME, @StartDate)

    DECLARE @FinishTime TIME
    SET @FinishTime = CONVERT(TIME, @FinishDate)

    DECLARE @WorkStart TIME
    SET @WorkStart = '09:00'

    DECLARE @WorkFinish TIME
    SET @WorkFinish = '17:00'

    DECLARE @DailyWorkTime BIGINT
    SET @DailyWorkTime = DATEDIFF(MINUTE, @WorkStart, @WorkFinish)

    IF (@StartTime<@WorkStart)
    BEGIN
        SET @StartTime = @WorkStart
    END
    IF (@FinishTime>@WorkFinish)
    BEGIN
        SET @FinishTime=@WorkFinish
    END
    IF (@FinishTime<@WorkStart)
    BEGIN
        SET @FinishTime=@WorkStart
    END
    IF (@StartTime>@WorkFinish)
    BEGIN
        SET @StartTime = @WorkFinish
    END

    DECLARE @CurrentDate DATE
    SET @CurrentDate = @FirstDay
    DECLARE @LastDate DATE
    SET @LastDate = @LastDay

    WHILE(@CurrentDate<=@LastDate)
    BEGIN       
        IF (DATEPART(dw, @CurrentDate)!=1 AND DATEPART(dw, @CurrentDate)!=7)
        BEGIN
            IF (@CurrentDate!=@FirstDay) AND (@CurrentDate!=@LastDay)
            BEGIN
                SET @Temp = @Temp + @DailyWorkTime
            END
            --IF it starts at startdate and it finishes not this date find diff between work finish and start as minutes
            ELSE IF (@CurrentDate=@FirstDay) AND (@CurrentDate!=@LastDay)
            BEGIN
                SET @Temp = @Temp + DATEDIFF(MINUTE, @StartTime, @WorkFinish)
            END

            ELSE IF (@CurrentDate!=@FirstDay) AND (@CurrentDate=@LastDay)
            BEGIN
                SET @Temp = @Temp + DATEDIFF(MINUTE, @WorkStart, @FinishTime)
            END
            --IF it starts and finishes in the same date
            ELSE IF (@CurrentDate=@FirstDay) AND (@CurrentDate=@LastDay)
            BEGIN
                SET @Temp = DATEDIFF(MINUTE, @StartTime, @FinishTime)
            END
        END
        SET @CurrentDate = DATEADD(day, 1, @CurrentDate)
    END

    -- Return the result of the function
    IF @Temp<0
    BEGIN
        SET @Temp=0
    END
    RETURN @Temp

END

SQL 2005 and below:

-- =============================================
-- Author:      Baran Kaynak (modified by Kodak 2012-04-18)
-- Create date: 14.03.2011
-- Description: 09:30 ile 17:30 arasındaki iş saatlerini hafta sonlarını almayarak toplar.
-- =============================================
CREATE FUNCTION [dbo].[WorkTime] 
(
    @StartDate DATETIME,
    @FinishDate DATETIME
)
RETURNS BIGINT
AS
BEGIN
    DECLARE @Temp BIGINT
    SET @Temp=0

    DECLARE @FirstDay DATETIME
    SET @FirstDay = DATEADD(dd, 0, DATEDIFF(dd, 0, @StartDate))

    DECLARE @LastDay DATETIME
    SET @LastDay = DATEADD(dd, 0, DATEDIFF(dd, 0, @FinishDate))

    DECLARE @StartTime DATETIME
    SET @StartTime = @StartDate - DATEADD(dd, DATEDIFF(dd, 0, @StartDate), 0)

    DECLARE @FinishTime DATETIME
    SET @FinishTime = @FinishDate - DATEADD(dd, DATEDIFF(dd, 0, @FinishDate), 0)

    DECLARE @WorkStart DATETIME
    SET @WorkStart = CONVERT(DATETIME, '09:00', 8)

    DECLARE @WorkFinish DATETIME
    SET @WorkFinish = CONVERT(DATETIME, '17:00', 8)

    DECLARE @DailyWorkTime BIGINT
    SET @DailyWorkTime = DATEDIFF(MINUTE, @WorkStart, @WorkFinish)

    IF (@StartTime<@WorkStart)
    BEGIN
        SET @StartTime = @WorkStart
    END
    IF (@FinishTime>@WorkFinish)
    BEGIN
        SET @FinishTime=@WorkFinish
    END
    IF (@FinishTime<@WorkStart)
    BEGIN
        SET @FinishTime=@WorkStart
    END
    IF (@StartTime>@WorkFinish)
    BEGIN
        SET @StartTime = @WorkFinish
    END

    DECLARE @CurrentDate DATETIME
    SET @CurrentDate = @FirstDay
    DECLARE @LastDate DATETIME
    SET @LastDate = @LastDay

    WHILE(@CurrentDate<=@LastDate)
    BEGIN       
        IF (DATEPART(dw, @CurrentDate)!=1 AND DATEPART(dw, @CurrentDate)!=7)
        BEGIN
            IF (@CurrentDate!=@FirstDay) AND (@CurrentDate!=@LastDay)
            BEGIN
                SET @Temp = @Temp + @DailyWorkTime
            END
            --IF it starts at startdate and it finishes not this date find diff between work finish and start as minutes
            ELSE IF (@CurrentDate=@FirstDay) AND (@CurrentDate!=@LastDay)
            BEGIN
                SET @Temp = @Temp + DATEDIFF(MINUTE, @StartTime, @WorkFinish)
            END

            ELSE IF (@CurrentDate!=@FirstDay) AND (@CurrentDate=@LastDay)
            BEGIN
                SET @Temp = @Temp + DATEDIFF(MINUTE, @WorkStart, @FinishTime)
            END
            --IF it starts and finishes in the same date
            ELSE IF (@CurrentDate=@FirstDay) AND (@CurrentDate=@LastDay)
            BEGIN
                SET @Temp = DATEDIFF(MINUTE, @StartTime, @FinishTime)
            END
        END
        SET @CurrentDate = DATEADD(day, 1, @CurrentDate)
    END

    -- Return the result of the function
    IF @Temp<0
    BEGIN
        SET @Temp=0
    END
    RETURN @Temp

END

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青春惊慌失措

2020-11-27 05:30

The first step would be to calculate working days, as shown in the script below:

DECLARE @TotalWorkDays INT, @TotalTimeDiff DECIMAL(18, 2), @DateFrom DATETIME, @DateTo DATETIME;
SET @DateFrom = '2017-06-05 11:19:11.287';
SET @DateTo = '2017-06-07 09:53:14.750';

SET @TotalWorkDays = DATEDIFF(DAY, @DateFrom, @DateTo)
    -(DATEDIFF(WEEK, @DateFrom, @DateTo) * 2)
   -CASE
                                    WHEN DATENAME(WEEKDAY, @DateFrom) = 'Sunday'
                                    THEN 1
                                    ELSE 0
                                END+CASE
                                        WHEN DATENAME(WEEKDAY, @DateTo) = 'Saturday'
                                        THEN 1
                                        ELSE 0
                                    END;

The second step involves getting a difference in seconds between the two dates and converting that difference into hours by dividing by 3600.0 as shown in this following script:

SET @TotalTimeDiff =
(
    SELECT DATEDIFF(SECOND,
                   (
                       SELECT CONVERT(TIME, @DateFrom)
                   ),
                   (
                       SELECT CONVERT(TIME, @DateTo)
                   )) / 3600.0
);

The last part involves multiplying the output the first step above by 24 (total number of hours in a day) and then later adding that to the output of the second step:

SELECT(@TotalWorkDays * 24.00) + @TotalTimeDiff;

Finally, the complete script that can be used to create a user defined function for calculating working hours is shown below:

CREATE FUNCTION [dbo].[fn_GetTotalWorkingHours]
(
    @DateFrom Datetime,
    @DateTo Datetime
)
RETURNS DECIMAL(18,2)
AS
BEGIN

DECLARE @TotalWorkDays INT, @TotalTimeDiff DECIMAL(18, 2)

SET @TotalWorkDays = DATEDIFF(DAY, @DateFrom, @DateTo)
    -(DATEDIFF(WEEK, @DateFrom, @DateTo) * 2)
   -CASE
                                    WHEN DATENAME(WEEKDAY, @DateFrom) = 'Sunday'
                                    THEN 1
                                    ELSE 0
                                END+CASE
                                        WHEN DATENAME(WEEKDAY, @DateTo) = 'Saturday'
                                        THEN 1
                                        ELSE 0
                                    END;
SET @TotalTimeDiff =
(
    SELECT DATEDIFF(SECOND,
                   (
                       SELECT CONVERT(TIME, @DateFrom)
                   ),
                   (
                       SELECT CONVERT(TIME, @DateTo)
                   )) / 3600.0
);

RETURN  (SELECT(@TotalWorkDays * 24.00) + @TotalTimeDiff)

END
GO

The complete method is descibed in this article: https://www.sqlshack.com/how-to-calculate-work-days-and-hours-in-sql-server/

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野趣味

2020-11-27 05:31

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
DECLARE @WORKINGHOURS INT
DECLARE @Days INT
SET @StartDate = '2010/01/01'
SET @EndDate = '2010/04/01'

--number of working days
SELECT @Days = 
   (DATEDIFF(dd, @StartDate, @EndDate) + 1)
  -(DATEDIFF(wk, @StartDate, @EndDate) * 2)
  -(CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
  -(CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)

--8 hours a day    
SET @WORKINGHOURS = @Days * 8 

SELECT @WORKINGHOURS

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花落未央

2020-11-27 05:33

Here's an alternative solution, without the use of a function. Note that this relies on the existence of a numbers table, populated with at least the maximum number of days the tasks you're tracking may take.

This doesn't take public holidays into account. If you don't work weekends, setting the opening and closing times to midnight in the @OpeningHours table variable should do the job.

I've tested this against 8500 rows of 'real world' data and found it to be performant.

DECLARE @OpeningHours TABLE ([DayOfWeek] INTEGER, OpeningTime TIME(0), ClosingTime TIME(0));

INSERT
    @OpeningHours ([DayOfWeek], OpeningTime, ClosingTime)
VALUES
    (1, '10:00', '16:00') -- Sun
    , (2, '06:30', '23:00') -- Mon
    , (3, '06:30', '23:00') -- Tue
    , (4, '06:30', '23:00') -- Wed
    , (5, '06:30', '23:00') -- Thu
    , (6, '06:30', '23:00') -- Fri
    , (7, '08:00', '20:00'); -- Sat

DECLARE @Tasks TABLE ([Description] VARCHAR(50), CreatedDateTime DATETIME, CompletedDateTime DATETIME);

INSERT
    @Tasks ([Description], CreatedDateTime, CompletedDateTime)
VALUES
    ('Make tea', '20170404 10:00', '20170404 10:12')
    , ('Make coffee', '20170404 23:35', '20170405 06:32')
    , ('Write complex SQL query', '20170406 00:00', '20170406 23:32')
    , ('Rewrite complex SQL query', '20170406 23:50', '20170410 10:50');

SELECT
    WorkingMinutesToRespond =
        SUM(CASE WHEN CAST(Tasks.CreatedDateTime AS DATE) = CAST(Tasks.CompletedDateTime AS DATE) THEN
        CASE WHEN CAST(Tasks.CreatedDateTime AS TIME) < OpeningHours.OpeningTime THEN
            -- Task created before opening time
            DATEDIFF(MINUTE, OpeningHours.OpeningTime, CAST(Tasks.CompletedDateTime AS TIME))
        ELSE
            DATEDIFF(MINUTE, Tasks.CreatedDateTime, Tasks.CompletedDateTime)
        END
    ELSE
        CASE WHEN Tasks.CoveredDate = CAST(Tasks.CreatedDateTime AS DATE) THEN 
            -- This is the day the task was created
            CASE WHEN CAST(Tasks.CreatedDateTime AS TIME(0)) > OpeningHours.ClosingTime THEN
                0 -- after working hours
            ELSE
                -- during or before working hours
                CASE WHEN CAST(Tasks.CreatedDateTime AS TIME(0)) < OpeningHours.OpeningTime THEN
                    -- before opening time; take the whole day into account
                    DATEDIFF(MINUTE, OpeningHours.OpeningTime, OpeningHours.ClosingTime)
                ELSE
                    -- during opening hours; take part of the day into account
                    DATEDIFF(MINUTE, CAST(Tasks.CreatedDateTime AS TIME), OpeningHours.ClosingTime)
                END
            END
        ELSE
            -- This is the day the task was completed
            CASE WHEN Tasks.CoveredDate = CAST(Tasks.CompletedDateTime AS DATE) THEN 
                CASE WHEN CAST(Tasks.CompletedDateTime AS TIME(0)) < OpeningHours.OpeningTime THEN
                    0 -- before working hours (unlikely to occur)
                ELSE
                    -- during or after working hours
                    CASE WHEN CAST(Tasks.CompletedDateTime AS TIME(0)) > OpeningHours.ClosingTime THEN
                        -- after closing time (also unlikely); take the whole day into account
                        DATEDIFF(MINUTE, OpeningHours.OpeningTime, OpeningHours.ClosingTime)
                    ELSE
                        -- during opening hours; take part of the day into account
                        DATEDIFF(MINUTE, OpeningHours.OpeningTime, CAST(Tasks.CompletedDateTime AS TIME(0)))
                    END
                END
        ELSE
            DATEDIFF(MINUTE, OpeningHours.OpeningTime, OpeningHours.ClosingTime)
        END 
        END
    END)
    , Tasks.Description
    , Tasks.CreatedDateTime
    , Tasks.CompletedDateTime
FROM
    (
        SELECT
        Tasks.Description
        , Tasks.CreatedDateTime
        , Tasks.CompletedDateTime
        , CoveredDate = CAST(DATEADD(DAY, Numbers.Number, Tasks.CreatedDateTime) AS DATE)
    FROM
        @Tasks Tasks
        INNER JOIN (SELECT * FROM Numbers WHERE Number >= 0) Numbers ON DATEDIFF(DAY, Tasks.CreatedDateTime, Tasks.CompletedDateTime) >= Numbers.Number
) Tasks
INNER JOIN @OpeningHours OpeningHours ON DATEPART(WEEKDAY, Tasks.CoveredDate) = OpeningHours.[DayOfWeek]
GROUP BY
    Tasks.Description
    , Tasks.CreatedDateTime
    , Tasks.CompletedDateTime
ORDER BY
    Tasks.CompletedDateTime;

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