Powershell: Two dimension arrays

Question

The following works as expected:

$values = @( (\"a\", \"b\"), (\"c\", \"d\") )
foreach($value in $values)
{
  write-host \"Value 0 =\" $value[0]
  write-host \"V         


        

Answer 1

This is another case where PowerShell's array handling behavior may cause unexpected results.

I think you'll need to use the comma trick (the array operator) to get the desired result:

$values = @( ,("a", "b") )
foreach($value in $values)
{
  write-host "Value 0 =" $value[0]
  write-host "Value 1 =" $value[1]
}

Result:

Value 0 = a
Value 1 = b

Actually all you need is this:

$values = ,("a", "b")

This article explains more about PowerShell's handling of arrays:

http://blogs.msdn.com/b/powershell/archive/2007/01/23/array-literals-in-powershell.aspx