How can I convert BitArray to single int?

Question

How can I convert BitArray to a single int?

Answer 1

private int getIntFromBitArray(BitArray bitArray)
{
    int value = 0;

    for (int i = 0; i < bitArray.Count; i++)
    {
        if (bitArray[i])
            value += Convert.ToInt16(Math.Pow(2, i));
    }

    return value;
}

Answer 2

This version:

• works for up to 64 bits
• doesn't rely on knowledge of BitArray implementation details
• doesn't needlessly allocate memory
• doesn't throw any exceptions (feel free to add a check if you expect more bits)
• should be more than reasonably performant

Implementation:

public static ulong BitArrayToU64(BitArray ba)
{
    var len = Math.Min(64, ba.Count);
    ulong n = 0;
    for (int i = 0; i < len; i++) {
        if (ba.Get(i))
            n |= 1UL << i;
    }
    return n;
}

Answer 3

Reffering to this post (#43935747). A value X is short tpe whic I set two bits (6 and 10) like below: short X=1;

        var result = X;
        var bitsToSet = new [ ] { 5,9 };
        foreach ( var bitToSet in bitsToSet )
            {
            result+=( short ) Math.Pow ( 2,bitToSet );
            }
        string binary = Convert.ToString ( result,2 );

Now I would like to read the specific all bits from Value X and put it in to an array or a bit type like bool Val1= bit1, bool Val2=bit2....

I am a newbie and I think it is pretty simple for you guyes..

Answer 4

private int getIntFromBitArray(BitArray bitArray)
{

    if (bitArray.Length > 32)
        throw new ArgumentException("Argument length shall be at most 32 bits.");

    int[] array = new int[1];
    bitArray.CopyTo(array, 0);
    return array[0];

}