i want to display the employee names which having names start with a and b ,it should be like list will display employees with \'a\' as a first letter and then the \'b\' as a
If you're asking about alphabetical order the syntax is:
SELECT * FROM table ORDER BY column
the best example I can give without knowing your table and field names:
SELECT * FROM employees ORDER BY name
select name_last, name_first
from employees
where name_last like 'A%' or name_last like 'B%'
order by name_last, name_first asc
select columns
from table
where (
column like 'a%'
or column like 'b%' )
order by column asc
What cfengineers said, except it sounds like you will want to sort it as well.
select columns
from table
where (
column like 'a%'
or column like 'b%' )
order by column
Perhaps it would be a good idea for you to check out some tutorials on SQL, it's pretty interesting.
Regular expressions work well if needing to find a range of starting characters. The following finds all employee names starting with A, B, C or D and adds the “UPPER” call in case a name is in the database with a starting lowercase letter. My query works in Oracle (I did not test other DB's). The following would return for example:
Adams
adams
Dean
dean
This query also ignores case in the ORDER BY via the "lower" call:
SELECT employee_name
FROM employees
WHERE REGEXP_LIKE(UPPER(TRIM(employee_name)), '^[A-D]')
ORDER BY lower(employee_name)
select employee_name
from employees
where employee_name LIKE 'A%' OR employee_name LIKE 'B%'
order by employee_name