Python 3 executable as windows service

Question

I\'m trying to write a windows Service in python, but the tricky part is i want to deploy it on a machine that doesn\'t have python. I\'ve successfully created a service like th

Answer 1

It appears Win32Service was updated with Python 3.x support within the cx_Freeze project as a result of this thread. This user originally had the same issue you reported, so I'm assuming this will also resolve your issue.

Based on the error reported, it's caused when _GetBaseFileName() within Freezer.py fails to find the compiled Win32Service.exe. This executable should be built when cx_Freeze gets built/installed.

If it's not too much to ask, can search the installed cx_Freeze installation directory for "Win32Service.exe" and confirm that it exists. Hopefully this gets you one step closer.

Answer 2

tldr Python 3.5 Windows Service build with pyinstaller : gist

Here a simple Windows Service with python :

WindowsService.py

import servicemanager
import socket
import sys
import win32event
import win32service
import win32serviceutil


class TestService(win32serviceutil.ServiceFramework):
    _svc_name_ = "TestService"
    _svc_display_name_ = "Test Service"

    def __init__(self, args):
        win32serviceutil.ServiceFramework.__init__(self, args)
        self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)
        socket.setdefaulttimeout(60)

    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        win32event.SetEvent(self.hWaitStop)

    def SvcDoRun(self):
        rc = None
        while rc != win32event.WAIT_OBJECT_0:
            with open('C:\\TestService.log', 'a') as f:
                f.write('test service running...\n')
            rc = win32event.WaitForSingleObject(self.hWaitStop, 5000)


if __name__ == '__main__':
    if len(sys.argv) == 1:
        servicemanager.Initialize()
        servicemanager.PrepareToHostSingle(TestService)
        servicemanager.StartServiceCtrlDispatcher()
    else:
        win32serviceutil.HandleCommandLine(TestService)

Create an exe with pyinstaller (pip install pyinstaller) and python 3.5 :

(env)$ python -V
Python 3.5.2

(env)$ pip freeze
PyInstaller==3.2

(env)$ pyinstaller -F --hidden-import=win32timezone WindowsService.py

Install and run the service

(env) dist\WindowsService.exe install
Installing service TestService
Service installed

(env) dist\WindowsService.exe start
Starting service TestService

Check C:\\TestService.log file.

Stop and clean

(env) dist\WindowsService.exe stop
(env) dist\WindowsService.exe remove

Answer 3

I've edited the Win32Service.c in the cx_freeze src for python3 support

Edited it with some preprocessor commands, for python2 support too (but not tested for python2 yet)

1. download sources of cx_freeze from pypi and extract it
2. download cx_logging and extract it to the cx_freeze-4.3.4 directory
3. replace the Win32Service.c file in cx_Freeze-4.3.4\source\bases with my edited version
4. edit line 170 in setup.py from if moduleInfo is not None and sys.version_info[:2] < (3, 0): to if moduleInfo is not None:
5. run python setup.py build in cx_freeze-4.3.4 directory (you must have MSC installed to compile the C source files)
6. copy cx_Freeze-4.3.4\build\lib.win32-3.4\cx_Freeze\bases\Win32Service.exe to C:\Python34\Lib\site-packages\cx_Freeze\bases (or the path where your python3 is installed)
7. now you can create frozen exe with the Win32Service base (no more the cx_Freeze.freezer.ConfigError: no base named Win32Service error)