I want my Python function to split a sentence (input) and store each word in a list. My current code splits the sentence, but does not store the words as a list. How do I do
I want my python function to split a sentence (input) and store each word in a list
The str().split()
method does this, it takes a string, splits it into a list:
>>> the_string = "this is a sentence"
>>> words = the_string.split(" ")
>>> print(words)
['this', 'is', 'a', 'sentence']
>>> type(words)
<type 'list'> # or <class 'list'> in Python 3.0
The problem you're having is because of a typo, you wrote print(words)
instead of print(word)
:
Renaming the word
variable to current_word
, this is what you had:
def split_line(text):
words = text.split()
for current_word in words:
print(words)
..when you should have done:
def split_line(text):
words = text.split()
for current_word in words:
print(current_word)
If for some reason you want to manually construct a list in the for loop, you would use the list append()
method, perhaps because you want to lower-case all words (for example):
my_list = [] # make empty list
for current_word in words:
my_list.append(current_word.lower())
Or more a bit neater, using a list-comprehension:
my_list = [current_word.lower() for current_word in words]
text.split()
This should be enough to store each word in a list. words
is already a list of the words from the sentence, so there is no need for the loop.
Second, it might be a typo, but you have your loop a little messed up. If you really did want to use append, it would be:
words.append(word)
not
word.append(words)
str.split()
Return a list of the words in the string, using sep as the delimiter ... If sep is not specified or is None, a different splitting algorithm is applied: runs of consecutive whitespace are regarded as a single separator, and the result will contain no empty strings at the start or end if the string has leading or trailing whitespace.
>>> line="a sentence with a few words"
>>> line.split()
['a', 'sentence', 'with', 'a', 'few', 'words']
>>>