Question about strpos: how to get 2nd occurrence of a string?

Question

I understand that this function will get the first occurrence of the string.

But what I want is the 2nd occurrence.

How to go about doing that?

Answer 1

//Finds nth occourance of string after position of given needle.
//Pass $needle argument as empty string [''] if you want to find from start
//Pass $needle argument as Int to search string from this position

function substr_Index( $string, $needle, $delimiter, $nth ){
    $str2 = '';
    $posf = strpos($string, $needle);
    if($posf !== false){
        $string   = substr($string, $posf);
        $posTotal = $posf;      
    }else{
        $posTotal = 0;
    }
    
    if( is_int($needle) ){
        $posTotal = $needle;
    }

    for($i=0; $i < $nth; $i++){
        
        if($str2 != ''){
            $string = $str2;
        }
             
        $pos   = strpos($string, $delimiter);
        $str2  = substr($string, $pos + 1);
        $posTotal += $pos+1;
        
    }
    return $posTotal-1;
}
               
//example (returns part of given string from second [:] next from first [#]  )
$str_ = '..:....:..:....#,61185:9789756130346:0000000:369615:97860510:61436=0000000323636';

echo substr($str_, substr_Index( $str_, '#' , ':', 2) );

Answer 2

You can try this, though I haven't tested it out-

$pos = strpos($haystack, $needle, strpos($haystack, $needle)+strlen($needle));