How do I select text nodes with jQuery?

Question

I would like to get all descendant text nodes of an element, as a jQuery collection. What is the best way to do that?

Answer 1

if you want to strip all tags, then try this

function:

String.prototype.stripTags=function(){
var rtag=/<.*?[^>]>/g;
return this.replace(rtag,'');
}

usage:

var newText=$('selector').html().stripTags();

Answer 2

$('body').find('*').contents().filter(function () { return this.nodeType === 3; });

Answer 3

For some reason contents() didn't work for me, so if it didn't work for you, here's a solution I made, I created jQuery.fn.descendants with the option to include text nodes or not

Usage

---

Get all descendants including text nodes and element nodes

jQuery('body').descendants('all');

---

Get all descendants returning only text nodes

jQuery('body').descendants(true);

---

Get all descendants returning only element nodes

jQuery('body').descendants();

---

Coffeescript Original:

jQuery.fn.descendants = ( textNodes ) ->

    # if textNodes is 'all' then textNodes and elementNodes are allowed
    # if textNodes if true then only textNodes will be returned
    # if textNodes is not provided as an argument then only element nodes
    # will be returned

    allowedTypes = if textNodes is 'all' then [1,3] else if textNodes then [3] else [1]

    # nodes we find
    nodes = []


    dig = (node) ->

        # loop through children
        for child in node.childNodes

            # push child to collection if has allowed type
            nodes.push(child) if child.nodeType in allowedTypes

            # dig through child if has children
            dig child if child.childNodes.length


    # loop and dig through nodes in the current
    # jQuery object
    dig node for node in this


    # wrap with jQuery
    return jQuery(nodes)

Drop In Javascript Version

var __indexOf=[].indexOf||function(e){for(var t=0,n=this.length;t<n;t++){if(t in this&&this[t]===e)return t}return-1}; /* indexOf polyfill ends here*/ jQuery.fn.descendants=function(e){var t,n,r,i,s,o;t=e==="all"?[1,3]:e?[3]:[1];i=[];n=function(e){var r,s,o,u,a,f;u=e.childNodes;f=[];for(s=0,o=u.length;s<o;s++){r=u[s];if(a=r.nodeType,__indexOf.call(t,a)>=0){i.push(r)}if(r.childNodes.length){f.push(n(r))}else{f.push(void 0)}}return f};for(s=0,o=this.length;s<o;s++){r=this[s];n(r)}return jQuery(i)}

Unminified Javascript version: http://pastebin.com/cX3jMfuD

This is cross browser, a small Array.indexOf polyfill is included in the code.

Answer 4

I was getting a lot of empty text nodes with the accepted filter function. If you're only interested in selecting text nodes that contain non-whitespace, try adding a nodeValue conditional to your filter function, like a simple $.trim(this.nodevalue) !== '':

$('element')
    .contents()
    .filter(function(){
        return this.nodeType === 3 && $.trim(this.nodeValue) !== '';
    });

http://jsfiddle.net/ptp6m97v/

Or to avoid strange situations where the content looks like whitespace, but is not (e.g. the soft hyphen ­ character, newlines \n, tabs, etc.), you can try using a Regular Expression. For example, \S will match any non-whitespace characters:

$('element')
        .contents()
        .filter(function(){
            return this.nodeType === 3 && /\S/.test(this.nodeValue);
        });

Answer 5

Jauco posted a good solution in a comment, so I'm copying it here:

$(elem)
  .contents()
  .filter(function() {
    return this.nodeType === 3; //Node.TEXT_NODE
  });

Answer 6

jQuery doesn't have a convenient function for this. You need to combine contents(), which will give just child nodes but includes text nodes, with find(), which gives all descendant elements but no text nodes. Here's what I've come up with:

var getTextNodesIn = function(el) {
    return $(el).find(":not(iframe)").addBack().contents().filter(function() {
        return this.nodeType == 3;
    });
};

getTextNodesIn(el);

Note: If you're using jQuery 1.7 or earlier, the code above will not work. To fix this, replace addBack() with andSelf(). andSelf() is deprecated in favour of addBack() from 1.8 onwards.

This is somewhat inefficient compared to pure DOM methods and has to include an ugly workaround for jQuery's overloading of its contents() function (thanks to @rabidsnail in the comments for pointing that out), so here is non-jQuery solution using a simple recursive function. The includeWhitespaceNodes parameter controls whether or not whitespace text nodes are included in the output (in jQuery they are automatically filtered out).

Update: Fixed bug when includeWhitespaceNodes is falsy.

function getTextNodesIn(node, includeWhitespaceNodes) {
    var textNodes = [], nonWhitespaceMatcher = /\S/;

    function getTextNodes(node) {
        if (node.nodeType == 3) {
            if (includeWhitespaceNodes || nonWhitespaceMatcher.test(node.nodeValue)) {
                textNodes.push(node);
            }
        } else {
            for (var i = 0, len = node.childNodes.length; i < len; ++i) {
                getTextNodes(node.childNodes[i]);
            }
        }
    }

    getTextNodes(node);
    return textNodes;
}

getTextNodesIn(el);